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How do you write a function in Python with variable arguments into the function and return variable number of outputs? Is this even possible with the constraints?

S. C.
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  • https://docs.python.org/2/tutorial/controlflow.html#more-on-defining-functions – BrenBarn Feb 16 '15 at 20:41
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    Please see http://stackoverflow.com/questions/36901/what-does-double-star-and-star-do-for-python-parameters . – Łukasz Rogalski Feb 16 '15 at 20:42
  • http://stackoverflow.com/questions/919680/python-can-a-variable-number-of-arguments-be-passed-to-a-function –  Feb 16 '15 at 20:43
  • @BrenBarn I think you mean [here](https://docs.python.org/2/tutorial/controlflow.html#arbitrary-argument-lists). – Malik Brahimi Feb 16 '15 at 20:50
  • @MalikBrahimi: Yes, but the discussion of `**kwargs` is before that so I decided to link to the top of the section. – BrenBarn Feb 16 '15 at 20:51

2 Answers2

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You mean like this. This is quite similar to ellipses in Java. When supplied with a variable amount of arguments, you can unpack these arguments as a list which you can manipulate as you deem necessary.

def func(*args):
    print len(args) # num of vars
Malik Brahimi
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yes you can, take a look at splat operator

def my_function(*a): #here a will be list or tuple depend wt u passed
    # do your stuff with a

**a for dictionary

Hackaholic
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