How to pass a value and echo it within a form

Question

hello i have a page where users can register, and so after registeration i want to pass the username and password from my registeration form to another form on a next page, mean while this form on the next page should hold username and password values that are passed from the first page.

the form is echoed correctly but the values dont come correctly.

this is what i ahve tried

echo '<form ACTION="<?php echo $loginFormAction; ?>" METHOD="POST" name="one" id="one">
              <input type="text" placeholder="Username" name="Username" value="<?php echo $_POST["Username"]; ?>" >
              <p>&nbsp;</p>
              <input type="password" placeholder="Password" name="Password" value="<?php echo $_POST["Password"]; ?>">
              <br>
              <input name="Submit" type="submit" class="btn" value="Sign In" />

              </form>';

but the values dont come out, is there a right way to echoe this thanks

possible duplicate of [PHP echo inside echo](http://stackoverflow.com/questions/17477025/php-echo-inside-echo) — Rizier123, Feb 17 '15 at 14:14
You can use `Session Variables` to store the values of the first form. — Prerak Sola, Feb 17 '15 at 14:15
@toluodumbo To correct your code look at the answer on the duplicate + look into `$_SESSION` for storing your values — Rizier123, Feb 17 '15 at 14:16
and then do wat, can u explain with an example using a form, — tolu odumbo, Feb 17 '15 at 14:16
You can learn the basics about session variables on the link: http://www.w3schools.com/php/php_sessions.asp . It would be better if you try this on your own instead of me giving you the solution. It will be good for your learning purpose. — Prerak Sola, Feb 17 '15 at 14:18
Firstly, you can't have PHP tags inside an echo (*why? You're already in PHP*), then echo inside that echo (*why? You're already echoing*). Second; show us the rest of your code. — Funk Forty Niner, Feb 17 '15 at 14:32

score 0 · Accepted Answer · answered Feb 17 '15 at 14:28

0

echo '<form ACTION="'.$loginFormAction.'" METHOD="POST" name="one" id="one">
              <input type="text" placeholder="Username" name="Username" value="'.$_POST["Username"].'" >
              <p>&nbsp;</p>
              <input type="password" placeholder="Password" name="Password" value=".'$_POST["Password"].'">
              <br>
              <input name="Submit" type="submit" class="btn" value="Sign In" />

              </form>';

Try This And Reply

answered Feb 17 '15 at 14:28

Varun Naharia

5,318
10
50
84

it works but i am now having this error Notice: Undefined variable: loginFormAction in C:\xampp\htdocs\kbluser\connect.php on line 29, which has to do with form action – tolu odumbo Feb 17 '15 at 14:39
then give some value to the variable $loginFormAction eg. $loginFormAction="targetfile.php" – Varun Naharia Feb 17 '15 at 14:41

score 0 · Answer 2 · answered Feb 17 '15 at 14:35

You don't do this with echo, because the echo is just some HTML on the other page. You can also save them.

What you want is a form most likely:

Page 1

<form action="page2.php" method="post">
    Name:  <input type="text" name="username" /><br />
    <input type="submit" name="submit" value="Send" />
</form>

Page2

<?php
echo "Your sent username: ", $_POST['username'];
?>

How to pass a value and echo it within a form

2 Answers2