How can I set all HTML code display except image HTML code

Question

Please see the picture below. I need to set my page like below.

I'm using PHP, to show the HTML code I got success.

<?php
$post = "<p>I like this</p>";
$get_post = htmlspecialchars($post);
?>

and the result will be :<p>I like this</p> <-- All html code display.

But now, if I have an image file,

<img src="logo.png"/>

It won't display the image, but html display.

What I want is, how can I set all HTML code display except image HTML code <img>?

Please see the image below for example.

enter image description here

Additional Information

1. We only have 1 variable, that's $post
2. Assume $post retrieve from database

Example 1: $post = "<html><p>a</p><img src='logo.png'/></html>";
Example 2: $post = "<img src='logo.png'/>";

Please see the picture above for example.

so the Image tag is coming in the middle of some tags or you are getting it direct `` — Afsar, Feb 18 '15 at 04:13
Hard to say, but `strip_tags()` http://php.net/strip_tags could be an option. You can choose which ones you want or don't want stripped out. — Funk Forty Niner, Feb 18 '15 at 04:25
you mean that image is displayed as an image not displaying code? — Joe Kdw, Feb 18 '15 at 04:27

score 0 · Answer 1 · edited May 23 '17 at 10:27

0

I think concat will do the thing. Comments are welcomed.

<?php
$post1 = "<p>I like this</p>";
$image= "<img src="logo.png"/>";
$post2= "<p>I like this Too</p>";
$get_post = htmlspecialchars($post1)." ".$image." ".htmlspecialchars($post2);
?>

Update

use htmlspecialchars_decode()

for img src you can visit here or this can solve your question.

edited May 23 '17 at 10:27

Community

1
1

answered Feb 18 '15 at 04:09

Nabin Kunwar

1,965
14
29

Hi, how about if I have just $post1? In $post1, I want the function detect show all HTML code except, so all html code will display except – HiDayurie Dave Feb 18 '15 at 04:21

score 0 · Answer 2 · edited Feb 18 '15 at 05:08

0

you can check if the string have one img tag, then use if condition to get the output:

$post = "<img src='logo.png'/>";
//$post = '<p>I like this</p>';

if(strpos($post, "<img") != false)
{
     echo $post;
}else{
    $get_post = htmlspecialchars($post);
    echo $get_post;
}

edited Feb 18 '15 at 05:08

Adrian Cid Almaguer

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answered Feb 18 '15 at 04:20

Afsar

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Hi @zan, How about if in $post, there is a and I want the code display? – HiDayurie Dave Feb 18 '15 at 04:23
Hi, give us all the possible cases so that we can give you answer, – Afsar Feb 18 '15 at 05:37
Hi Zan, please see my additional information in my question. Please see the image for example. I think you will understand about my question. – HiDayurie Dave Feb 18 '15 at 05:46
do you want example one to display image – Afsar Feb 18 '15 at 05:48

Joe Kdw · Answer 3 · 2015-02-18T04:39:30.743

0

Still confused of your question for my bad English. Perhaps this helps.

<?php
$post='<img src="image/america.png"/>';
echo $post;
 ?>

UPDATED:

<?php
$post='<img src="image/america.png"/>';
//$post='<p>Hallo</p>';
$detect=substr($post,0,4);
if ($detect){
echo $post;
}
else{
$get_post = htmlspecialchars($post);
echo $get_post;
}
?>

edited Feb 18 '15 at 04:39

answered Feb 18 '15 at 04:31

Joe Kdw

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How can I set all HTML code display except image HTML code

3 Answers3