I have multiple images with a custom profile embedded in them and want to convert the image to sRGB in order to serve it up to a browser. I have seen code like the following:
BufferedImage image = ImageIO.read(fileIn);
ColorSpace ics = ColorSpace.getInstance(ColorSpace.CS_sRGB);
ColorConvertOp cco = new ColorConvertOp(ics, null);
BufferedImage result = cco.filter(image, null);
ImageIO.write(result, "PNG", fileOut);
where fileIn
and fileOut
are File objects representing the input file and output file respectively. This works to an extent. The problem is that the resulting image is lighter than the original. If I was to convert the color space in photoshop the colors would appear the same. In fact if I pull up both images with photoshop and take a screen shot and sample the colors, they are the same. What is photoshop doing that the code above isn't and what can I do to correct the problem?
There are various types of images being converted, including JPEG, PNG, and TIFF. I have tried using TwelveMonkeys to read in JPEG and TIFF images and I still get the same effect, where the image is too light. The conversion process seems worst when applied to an image that didn't have an embedded profile in the first place.
Edit:
I've added some sample images to help explain the problem.
- This image is the one with the color profile embedded in it. Viewed on some browsers there won't be a noticeable difference between this one and the next but viewed in Chrome on Mac OSX and Windows it currently appears darker than it should. This is where my problem originates in the first place. I need to convert the image to something that will show up correctly in Chrome.
- This is an image converted with ImageMagick to the Adobe RGB 1998 color profile, which Chrome appears to be able to display correctly.
- This is the image that I converted using the code above and it appears lighter than it should.
(Note that the images above are on imgur so to make them larger, simply remove the "t" from the end of the filename, before the file extension.)