C++03: _ui64toa_s: error C2446: ':' : no conversion from 'errno_t' to 'const char *'

Question

I have the following line of code:

(total_time== 0xAAAABBBB) ? ("") : _ui64toa_s(total_time, myArray, 1024, 10);

As the title suggests, I receive this error:

error C2446: ':' : no conversion from 'errno_t' to 'const char *'

I am unsure how to convert errno_t to const char *.

I tried to solve it by writing

 const char *n = _ui64toa_s(total_time, myArray, 1024, 10);

only to see this:
error C2440: 'initializing' : cannot convert from 'errno_t' to 'const char *'

I suspect that `_ui64toa_s` does not RETURN the string, but an error code. Both parts of the conditional operator must yield the same type. — Neil Kirk, Feb 20 '15 at 01:13
errno_t. I am forced to use this instead of the ui64toa, because our stdlib does not have ui64toa defined — user3555181, Feb 20 '15 at 01:23

score 0 · Answer 1 · edited May 23 '17 at 10:24

0

_ui64toa_s does not return a string like _ui64toa does.

Instead it returns an errno_t which is defined as int.

errno_t e = _ui64toa_s(total_time, myArray, 1024, 10);

But since you're using C++ I recommend you use std::to_string instead.

std::to_string(total_time).c_str();

You might also want to take a look at this question.

edited May 23 '17 at 10:24

Community

answered Feb 20 '15 at 01:30

Axalo

unfortunately I am using c++ 03, to_string not available to me – user3555181 Feb 20 '15 at 02:01

1 Answers1