Index out of range exception

Question

Sir i got index out of range exception in these code Can anybody explain me where i did mistake

if (SelectedRowtt > -1)
{   
    dgvSItt.Rows[SelectedRowtt].Cells["Item_Code"].Value =txtItemCode.Text;
    dgvSItt.Rows[SelectedRowtt].Cells["Description"].Value = txtDescription.Text;
    dgvSItt.Rows[SelectedRowtt].Cells["Qty"].Value = Convert.ToDecimal(txtQty.Text).ToString(Program.gDigitsAfterDecimal);
    dgvSItt.Rows[SelectedRowtt].Cells["UOM"].Value = Convert.ToDecimal(txtUOM.Text).ToString(Program.gDigitsAfterDecimal);

    gvSItt.Rows[SelectedRowtt].Cells["Amount"].Value = Convert.ToDecimal(txtAmount.Text).ToString(Program.gDigitsAfterDecimal);
    dgvSItt.Rows[SelectedRowtt].Cells["Discount"].Value = Convert.ToDecimal(txtRate.Text).ToString(Program.gDigitsAfterDecimal);
    SelectedRowtt = -1;
}
else
{
    IsDO = false;
    dgvSItt.Rows.Add();
    SelectedRowtt = -1;
}

dgvSItt has no Rows maybe? Did you check if it has any rows in it before processing it? — user3021830, Feb 20 '15 at 10:15
The best answer to your question is: Learn to use the debugger. This is simply a matter to check what is the value of SelectedRowtt at the exception time against the number of rows in your grid — Steve, Feb 20 '15 at 10:18

score 0 · Answer 1 · edited Feb 20 '15 at 10:24

0

You get that message when you have used an index on an array (or collection) that is not valid. For instance you may have an array defined for myArray[0] up to myArray[10]. If you tried to access myArray[-1] or myArray[11] you would get the error.

In your case it could be on the rows or the cells collections.

edited Feb 20 '15 at 10:24

Hamid Pourjam

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answered Feb 20 '15 at 10:17

Astra Bear

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score 0 · Answer 2 · edited Feb 20 '15 at 10:26

0

Depends on how you get SelectedRowtt. Usualy such exception happens because indexes start with 0 and end with Rows.Count -1 and you try to get dgvSItt.Rows[Rows.Count].

edited Feb 20 '15 at 10:26

Robert

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answered Feb 20 '15 at 10:20

f1sherox

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Index out of range exception

2 Answers2