Printing the value of items in array

Asked Feb 20 '15 at 11:26

Active Feb 20 '15 at 11:26

Viewed 13 times

I have a variable set as:

X="AA BB CC DD EE"
Y="AA DD EE"

Then each value have its own values assigned as below:

AA="after"
BB="before"
CC="care"
DD="driver"
EE="escape"

Then I need to loop through these variables and need to get its corresponding values to be printed.

for myloop in `echo $Y`
do
    # Now I need to print each variable  
    echo ${$myloop} # if its value is number then I can use ((myloop)) to print it
done

The output should be:

after
driver
escape

How can I achieve this using shell script? I am not using any array.

asked Feb 20 '15 at 11:26

Jagath

You are looking for variable indirection. Given `name=a` and `a=text` `${!name}` returns the value in `$a`. – fedorqui Feb 20 '15 at 11:29
1

That is bash-specific, though. A POSIX way is to `eval var="\$$myloop"` and then use `$var`. – Wintermute Feb 20 '15 at 11:34

Printing the value of items in array

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