How can I extract a file name with dat extension in python?

Question

There are many files in a folder like

sample-file.dat host-111.222.333.444.dat win.2k3.dat hello.micro.world.dat

I was using split

 file = os.path.basename(path) 
filename = file.split(".")[0]

but it does not work for all files, is there a better way to read whole filename even with dots and ignore only .dat extension

score 3 · Answer 1 · edited May 23 '17 at 12:12

3

Try

if file.endswith('.dat'):
    filename = file[:-4]

file[:-4] means get the string file and remove the last four characters

edited May 23 '17 at 12:12

Community

answered Feb 24 '15 at 23:50

deadbeef404

why are we using file[:-4] ? – lean john learner Feb 24 '15 at 23:51
@leanjohnlearner That means removing the last four characters (`.dat` in this case). – cdonts Feb 24 '15 at 23:53

score 3 · Answer 2 · answered Feb 24 '15 at 23:51

3

I would use rfind:

>>> s = "host-111.222.333.444.dat"
>>> filename = s[:s.rfind(".")]
>>> filename
'host-111.222.333.444'

It's like find(), but it returns the highest index.

Hope it helps!

answered Feb 24 '15 at 23:51

cdonts

score 3 · Answer 3 · answered Feb 24 '15 at 23:51

if they have multiple points, slice and recombine with join !

file = os.path.basename(path) 
filename = ".".join(file.split(".")[:-1])

This will remove what's after the last point, without checking the content,i.e.

3 Answers3