Creating an Eigen matrix from an array with row-major order

Question

I have an array of doubles, and I want to create a 4-by-4 matrix using the Eigen library. I also want to specify that the data is stored in row-major order. How can I do this?

I have tried the following, but it does not compile:

double data[16];
Eigen::Matrix4d M = Eigen::Map<Eigen::Matrix4d>(data, 4, 4, Eigen::RowMajor);

What in ggael's answer is lacking? If it answers your question, you should mark it as the answer to your question. If not, post a response with details on what additional help you need. — Phil, Mar 11 '15 at 17:32

score 20 · Accepted Answer · answered Feb 26 '15 at 15:23

20

You need to pass a row-major matrix type to Map, e.g.:

Map<Matrix<double,4,4,RowMajor> > M(data);

then you can use M as an Eigen matrix, and the values of data will be modified, e.g.:

M = M.inverse();

If you want to copy the data to a true column-major Eigen matrix, then do:

Matrix4d M = Map<Matrix<double,4,4,RowMajor> >(data);

Of course, you can also copy to a row-major matrix by using the right type for M.

answered Feb 26 '15 at 15:23

ggael

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Use Dynamic and pass the sizes to the ctor: `Map >(data, nbRows, nbColumns);` – ggael Jan 22 '17 at 20:58

score 1 · Answer 2 · answered Aug 31 '21 at 14:49

RowMajor forms actually come in handy when using arrays to store data sometimes. Hence you can also prefer using a typedef to RowMajor type.

namespace Eigen{ 
    typedef Eigen::Matrix<float, Eigen::Dynamic, Eigen::Dynamic, Eigen::RowMajor> MatrixXfRowMajor;
}

You can replace by float by any datatype of choice. For a 4x4 matrix then, we can simply do

Eigen::MatrixXfRowMajor mat;
mat.resize(4,4);

Creating an Eigen matrix from an array with row-major order

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