How to capture only last match in Regex

Question

I have the string below (including line breaks) that is returned from a TFS 'Labels' command. I need to match against only the last build number (build.2).

How do I build a regex expression to do this?

Label                                                  Owner          Date      
---------------------------------------------------- -------------- ---------- 
ICSExternalGateway-04_MJR-ICSExternalGateway-build.0 Marchen, Keith 2/25/2015 
ICSExternalGateway-04_MJR-ICSExternalGateway-build.1 Marchen, Keith 2/25/2015
ICSExternalGateway-04_MJR-ICSExternalGateway-build.2 Marchen, Keith 2/25/2015

What **language** are you using? – hwnd Feb 26 '15 at 04:39 — hwnd, Feb 26 '15 at 04:39

score 1 · Answer 1 · answered Feb 26 '15 at 04:19

1

build\.\d+(?![\s\S]*\bbuild\.\d+)

Try this.See demo.The lookahead will make sure there is no build ahead.

https://regex101.com/r/wU7sQ0/14

answered Feb 26 '15 at 04:19

vks

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score 0 · Answer 2 · answered Feb 26 '15 at 05:09

0

You might try something like this. It works because ordinarily the wildcard character . does not match a newline:

(build.\d).*$

See Regex 101 Demo here for example and full explanation.

answered Feb 26 '15 at 05:09

David Faber

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How to capture only last match in Regex

2 Answers2

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