Although I manage to send the grid's selected row id to the controller, the url for opening action view cannot be built up (it is created /Controller/Action instead of /Controller/Action/id. So, when I try to open the view with /Controller/Action/id it is open, but it cannot be opened by button click as below.
View:
<input type="button" id="btn" name="name" value="send to Server!" />
<script>
$('#btn').click(function () {
var items = {};
var grid = $('#Grid').data('kendoGrid');
var selectedElements = grid.select();
var item = grid.dataItem(selectedElements[0]);
$.ajax({
type: "POST",
data: item.ID, //I obtained the id properly
url: '@Url.Action("CreateParticipant", "Training")',
success: function (result) {
//console.log(result);
}
})
})
</script>
Controller:
// GET: /Training/CreateParticipant/5
public ActionResult CreateParticipant(int? id)
{
Training training = repository.Trainings.FirstOrDefault(m => m.ID == id);
if (training == null)
{
return HttpNotFound();
}
var trainingParticipantViewModel = new TrainingParticipantViewModel(training);
return View(trainingParticipantViewModel);
}
Route.config:
public class RouteConfig
{
public static void RegisterRoutes(RouteCollection routes)
{
routes.IgnoreRoute("{resource}.axd/{*pathInfo}");
routes.MapRoute(
name: "Default",
url: "{controller}/{action}/{id}",
//defaults: new { controller = "Home", action = "Index", id = UrlParameter.Optional }
defaults: new { controller = "Multiplier", action = "Index", id = UrlParameter.Optional }
);
}
}
Is there another example as above to pass the parameters or is there any mistake on the code above? Thanks in advance.