Parse error: syntax error, unexpected end of file in C:\xampp\htdocs\inc\data_forms\weight_routine_selector.php on line 84

Question

please some one help me am getting an parse error while inserting data into mysql database through my script

ive also changed its code like to:

?>

still not working... its showing the same error as unexpected ending and thanks in advance ........##

<?php
$conn = connect($config['db']);
if (!$conn)
    die("Could not connect to DB");
$user_id       = $_SESSION['myuserid'];
$user_row      = user_information_row($conn, $user_id);
$routine_names = get_active_routine_names($conn, $user_id);
?>

<style>
    .selection_block{
        background: rgb(119, 193, 88);
    }
</style>



<div class="page">
    <div class="information">
    <div class="title_nav">
        <h1 style="display:inline;">Add Inputs</h1>
        <p><a href="input?weights">view</a></p> 
        <p><a href="input?n">add</a></p>
        <p><a href="input?n_edit">edit</a></p> 
        <p><a href="input">| menu</a></p> 
    </div>

<form action="" method="post">  

    <?php
if (count($routine_names)):
?> 

    <?php
    if ($user_row['help']):
?>
      <div class="help">
        Select the routine you wish to use!
      </div>
    <?php
    endif;
?>

    <p>Select today's routine!</p>    
    <div> 
        <?php
    foreach ($routine_names as $name) {
        $exercise_ids_query = $conn->query("SELECT exerciseIdF FROM tbl_routines WHERE userIdF = $user_id AND routineName = '$name' AND active = TRUE");
        $exercise_ids       = $exercise_ids_query->fetchALL(PDO::FETCH_ASSOC);
        $str_exercise_names = "";
        foreach ($exercise_ids as $exerciseId) {
            $id                  = $exerciseId['exerciseIdF'];
            $exercise_name_query = $conn->query("SELECT name FROM tbl_exercises WHERE exerciseId = $id AND active = true");
            $exercise_name       = $exercise_name_query->fetchALL(PDO::FETCH_ASSOC);
            $str_exercise_names .= $exercise_name[0]['name'] . ', ';
        }
        $str_exercise_names = substr($str_exercise_names, 0, -2);
        $str_exercise_names .= '.';
        echo '<a href="input?n&name=' . $name . '"><div class="routine_selection"><p>' . $name . ' - ' . $str_exercise_names . '</p></div></a>';
    }
?> 
    </div>

    <?php
else:
?>
        <div class="help">
            No active routines, click <a href="input.php?r"style="text-decoration: underline; font-weight:bold; color:white">here</a> to make one.
        </div> 
    <?
endif;
?>
</form>
    
    </div>
</div>

<?php
if (isset($_GET['input_status'])){
    echo "<div id=\"notify\" class=\"success\">" . $_GET['input_status'] . "</div>";
}
?>

## Please help me in this ##

Answer 1

The problem with your code is that you have an <? in

<?
endif;
?>

which if short open tags are not set, then it will cause that parse error.

Either you enable them, or change <? to <?php

More on short open tags:

• http://php.net/manual/en/language.basic-syntax.phptags.php
• How to enable PHP short tags?

---

Additional notes.

If you have more code that you're not showing us and it contains <?= then that will also add to the problem.

You would need to change <?= to <?php echo as <?= is short tag syntax for <?php echo.