Parsing command line with getopt_long()

Question

I cant seem to obtain multiple command line arguments using getopt_long(). my code segfaults after it prints 1. I have another way to parse command line but it s killing me that this isnt working. Its so simple. Any ideas? thanks

int main(int argc, char** argv) {
int val;
std::string clcf;
int futures (0), blocks(0);


static struct option long_options[] =
{
    { "config"          , required_argument     , 0     , 'c' },
    { "sstest"            , optional_argument     , 0     , 's' },
    { "btest"          , optional_argument     , 0     , 'b' },
  //{ "ssfspreads"      , optional_argument     , 0     , 'S' },
  //{ "blockspreads"    , optional_argument     , 0     , 'B' },
    { 0                 , 0                     , 0     ,  0  }
};

while ((val = getopt_long (argc, argv, GETARGLIST.c_str(), long_options, 0)) != -1)
{

    switch (val)
    {
        case 'c': clcf = optarg; break;
        case 's': 
            std::cout << "1" << std::endl;

            futures = atoi( optarg ); break;

            std::cout << "2"  << futures <<  std::endl;
            break;
        case 'b': 
            std::cout << "1" << std::endl;
            //blocks = atoi(optarg); 
            break;
        //case 'ss': ssf_spreads = get_value<unsigned>(optarg); break;
        //case 'bs': block_spreads = get_value<stdunsigned>(optarg); break;
        default: break;
    }
}

When you are using non standard stuff, you should mention it. I guess this is the GNU getopt_long from the getopt.h but it could be anything. — 463035818_is_not_an_ai, Feb 27 '15 at 15:03

score 0 · Answer 1 · edited May 23 '17 at 11:56

0

How are you passing the arguments? You should pass the arguments without a space, otherwise it will segfault. This has the details: getopt does not parse optional arguments to parameters

edited May 23 '17 at 11:56

Community

1
1

answered Feb 27 '15 at 15:29

Prashanth

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Parsing command line with getopt_long()

1 Answers1