Using in_array correctly with array inside array

Question

I want to use in_array to check multiple integers, e.g checking integer "427971780" key: amenityId if exist anywhere in the array of a array.

The structure of the array is:

array(43) {
[0]=>
 array(2) {
 ["amenityId"]=>
 int(427971780)
 ["amenity"]=>
 string(28) "24-timers fitnessfaciliteter"
}
[1]=>
 array(2) {
 ["amenityId"]=>
 int(359778141)
 ["amenity"]=>
 string(27) "Antal bygninger/hÃ¸jhuse -3"
}

I'm using this php trying to look into the arrays an finding the integer but it doesen't seem to work.

If I do a

var_dump($hotelAmenities[0]['amenityId']);

it works fine. But I need it to be dynamic, looking up multiple integers. That's the reason for the IF sentence.

 for($x=0;$x<50;$x++){
if(in_array("427971780", $hotelAmenities[$x]['amenityId'])){
 echo "<li><i class='im im-bar'></i><span class='booking-item-feature-title'>Bar/Lounge</span></li>";
 }
 }

Can anyone spot for is wrong with the for/if code above?

possible duplicate of [in\_array() and multidimensional array](http://stackoverflow.com/questions/4128323/in-array-and-multidimensional-array) — Rizier123, Feb 28 '15 at 15:24

score 0 · Accepted Answer · edited May 23 '17 at 11:43

0

Your code is wrong. Try this.

for ($x = 0; $x < 50; $x ++) {
    if (in_array('427971780', $hotelAmenities[$x])) {
        echo "<li><i class='im im-bar'></i><span class='booking-item-feature-title'>Bar/Lounge</span></li>";
    }
}

And try to use this method in_array() and multidimensional array.

edited May 23 '17 at 11:43

Community

1
1

answered Feb 28 '15 at 15:49

Wilon

117
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6

Using in_array correctly with array inside array

1 Answers1