round integer if output comes in decimal

Question

var1=126
var2=16 
var1/var2 = 7.87

My requirement is if the output value comes in decimal, then add 1 to the integer i.e in this case 7+1 =8. How can I do that?

It seems you are looking for the ceiling function in `bash`. Here are hints how to do so: (http://stackoverflow.com/questions/2394988/get-ceiling-integer-from-number-in-linux-bash)[http://stackoverflow.com/questions/2394988/get-ceiling-integer-from-number-in-linux-bash] People use `awk` or they invoke a script. — peter_the_oak, Mar 01 '15 at 08:34
Typos, typos, typos.... [Question is here](http://stackoverflow.com/questions/2394988/get-ceiling-integer-from-number-in-linux-bash) — peter_the_oak, Mar 01 '15 at 08:39

score 1 · Accepted Answer · answered Mar 01 '15 at 08:49

1

You can use the modulo operator %:

#! /bin/bash
var1=126
var2=16
(( result = var1 / var2 ))
(( var1 % var2 && ++ result )) # If there's a remainder, add 1 to result.
echo $result

answered Mar 01 '15 at 08:49

choroba

1 Answers1