Python 2.7 Initialize multiple inheritors

Asked Mar 01 '15 at 11:59

Active Mar 01 '15 at 12:19

Viewed 78 times

I am trying to to run the following piece of code, and I want C to initialize both A and B (and possible more) in a neat and dynamic manner.

class A(object):
    def __init__(self):
        print 'Class A init'

class B(object):
    def __init__(self):
        print 'Class B init'

class C(A, B):
    def __init__(self):
        super(C, self).__init__()
        print 'Class C init'

c = C()

However, this only outputs

 Class A init
 Class C init

I know that this is due to the depth-first search manner when invoking super(...), and it stops when first method was found. Can I in some way initialize all super classes?

Edit: Defining C as below achieves the goal of initializing all super classes. Is there a way to implicit initialize all super classes?

class C(A, B):
    def __init__(self):
        A.__init__(self)
        B.__init__(self)
        print 'Class C init'

Solution: As pointed out a super(B, self).__init__() was added in class B

edited Mar 01 '15 at 12:19

asked Mar 01 '15 at 11:59

YnkDK

Why don't you call `super(B, self).__init__()` in `B` ? Can't think of a design where you really would want `C` to do both... – Jon Clements Mar 01 '15 at 12:07
1

duplicate of http://stackoverflow.com/q/8688114/3004881 – Dan Getz Mar 01 '15 at 12:09
`B` does not inherit `A` – YnkDK Mar 01 '15 at 12:09
@JonClements: I stand corrected. That worked. I did not know that. – YnkDK Mar 01 '15 at 12:11
This is a pretty bad way of inheriting. Why not just use a mixin for the behavior that you do want? – Games Brainiac Mar 01 '15 at 12:13

Python 2.7 Initialize multiple inheritors

0 Answers0