PHP - Add one week to a user defined date

Question

There's more than likely going to be a duplicate for this question, but I'm struggling to find a precise answer for my problem.

The user enters a starting date for a client's rent (on a form on a previous page), then it needs to generate the next date (one week later) that the client is required to pay. For example:

$start_date = $_POST['start_date'];  
$date_to_pay = ???

Lets say the user enters in 2015/03/02:

$start_date = "2015/03/02";

I then want the date to pay to be equal to a week later (2015/03/09):

$date_to_pay = "2015/03/09";

How would one go around doing this? Many thanks.

Yes! There are many, many duplicates: `$_POST['start_date'] = '2015/03/02'; $date = new DateTime($_POST['start_date']); $date->add(new DateInterval('P1W')); echo $date->format('Y/m/d');` — Mark Baker, Mar 02 '15 at 10:44
create date time from user input then add a week on it. For code see @MarkBaker 's comment — Nabin Kunwar, Mar 02 '15 at 10:44
check this link : http://stackoverflow.com/questions/6086389/php-date-format-yyyy-mm-dd-minus-or-add-one-week-from-now — jems, Mar 02 '15 at 10:47

score 25 · Accepted Answer · answered Mar 02 '15 at 10:45

25

You can try this

$start_date = "2015/03/02";  
$date = strtotime($start_date);
$date = strtotime("+7 day", $date);
echo date('Y/m/d', $date);

answered Mar 02 '15 at 10:45

priya786

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Sidenote: + 7 days is nice, but you could also just do + 1 week, just personnal preference.. – Naruto Mar 02 '15 at 10:52
3

One should note that this is a very poor method of doing this, `strtotime` returns seconds since epoch, you can simply add one week in seconds to the time and avoid the extra slow call to `strtotime`. `$date = strtotime($start_date) + 604800;` – HostFission Sep 13 '17 at 08:44

Mihir Bhatt · Answer 2 · 2020-06-17T05:32:58.677

15

Please try the following:

date('d.m.Y', strtotime('+1 week', strtotime($start_date)));

edited Jun 17 '20 at 05:32

answered Mar 02 '15 at 10:44

Mihir Bhatt

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So would I make $date_to_pay = date('d.m.Y', strtotime('+1 week', $start_date));?? – jarnold Mar 02 '15 at 10:59
Exactly, set as per your format Y/m/d. – Mihir Bhatt Mar 02 '15 at 11:02
I'm just trying it again cos for some reason my $date_to_pay came out as 1970/01/07 lol – jarnold Mar 02 '15 at 11:11
@bob Yeah I don't know why but for some reason it outputs the $date_to_pay as 1970/01/07??? – jarnold Mar 02 '15 at 17:07
@Jack, `$start_date` is meant to be a unix timestamp, [see manual](http://php.net/manual/en/function.strtotime.php#refsect1-function.strtotime-description) – halfpastfour.am Mar 03 '15 at 13:37

Anthony · Answer 3 · 2015-03-02T11:10:31.850

Object Oriented Style using DateTime classes:

$start_date = DateTime::createFromFormat('Y/m/d', $_POST['start_date']);

$one_week = DateInterval::createFromDateString('1 week');

$start_date->add($one_week);

$date_to_pay = $start_date->format('Y/m/d');

Or for those who like to have it all in one go:

$date_to_pay = DateTime::createFromFormat('Y/m/d',$_POST['start_date'])
                       ->add(DateInterval::createFromDateString('1 week'))
                       ->format('Y/m/d');

score 2 · Answer 4 · answered Mar 02 '15 at 10:56

2

$start_date = "2015/03/02";  
$new_date= date("Y/m/d", strtotime("$start_date +1 week"));

answered Mar 02 '15 at 10:56

TECHNOMAN

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score 2 · Answer 5 · edited Jun 12 '18 at 04:25

2

You can use this:

$startdate = $_POST['start_date'];
$date_to_pay = date('Y/m/d',strtotime('+1 week',$startdate));

edited Jun 12 '18 at 04:25

mochaMame

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answered Mar 02 '15 at 10:56

Narendrasingh Sisodia

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PHP - Add one week to a user defined date

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