PHP write contents to file with user submitted data

Question

I am trying to write contents to a file with user submitted data. I have some text say "my name is" and after this text i want to write user submitted value. How do i do this? I trying to do this with code given below.

<?php
  $fname=$_POST['fname'];
  $lname=$_POST['lname'];
  $my_file='file.txt';
  $handle= fopen($my_file,'w+');
  $data= 'My fname is $name and My lname is $lname';
  $fwrite($handle,$data);
?>

When i run this code $name does not take the input value and writes as $name like

"My name is $name"

How to fix this?

You have to put it in double quotes! e.g. `$data= "My name is $name";` (Just wait for the vampires) — Rizier123, Mar 03 '15 at 11:23

score 0 · Answer 1 · answered Mar 03 '15 at 11:24

0

To get a PHP variable to output, you need to use double quotes.

$data= "My name is $name";

or

$data = 'My name is '.$name;

answered Mar 03 '15 at 11:24

Albzi

15,431
6
46
63

score 0 · Answer 2 · answered Mar 03 '15 at 11:24

0

Try this:

<?php
$name=$_POST['name'];
$my_file='file.txt';
$handle= fopen($my_file,'w+');
$data= 'My name is ' . $name;
$fwrite($handle, $data);
?>

answered Mar 03 '15 at 11:24

Whatevaulike

1

score 0 · Accepted Answer · edited May 23 '17 at 12:06

You need to access the variable $name while writing the name to the file. The way you are doing it now does not add the value of the variable in the string. To do so you can change :

$data= 'My fname is $name and My lname is $lname';

to

$data= "My fname is $name and My lname is $lname";

The double quotes substitute the value of the variables in the string literal as it is evaluated before it is used in the expression. For more info refer this answer.

or

$data= 'My fname is '.$name.' and My lname is '.$lname;

Here, the string literal is concatenated with the value of the variables using the . operator.

score 0 · Answer 4 · answered Mar 03 '15 at 11:26

0

You have to concat your string with variable.

<?php
  $name=$_POST['name'];
  $my_file='file.txt';
  $handle= fopen($my_file,'w+');
  $data= 'My name is '.$name;
  $fwrite($handle,$data);
  $fclose($handle);
?>

answered Mar 03 '15 at 11:26

Szaby

39
3

score 0 · Answer 5 · answered Mar 03 '15 at 11:26

0

In PHP, variable returns value only in double quoted, single quote treat it as string.

answered Mar 03 '15 at 11:26

Vegeta

1,319
7
17

score 0 · Answer 6 · answered Mar 03 '15 at 12:20

<?php
     $fname=$_POST['fname']; 
     $lname=$_POST['lname'];
     $my_file='file.txt';
     $handle= fopen($my_file,'w+');
     $data= "My fname is $name and My lname is $lname"; // Change the quote from single to double. for php to parse and replace the variable with it's value but single quote is a literal
      $fwrite($handle,$data);
?>

PHP write contents to file with user submitted data

6 Answers6