Regular expression to validate A123456

Question

What is a suitable regular expression to validate that a string matches the format A123456

First letter must be a letter upper case or lower case then exactly 6 numeric numbers following it.

I'm using c# .net if that has any effect on the formatting.

Needed the answer in a rush and i was getting confused reading examples and figured the kind people here would help clarify for me. Thanks for the help. — Jammy, Mar 03 '15 at 13:42

Mr. Polywhirl · Accepted Answer · 2015-03-03T13:51:15.210

2

Well, you need to search for the following pattern:

((?i)) - [Modifiers] Case-insensitive
(^) - Begin
- ([a-z]) - A single letter
- (\d{6}) - Digits 0-9 with length of 6
( $) - End

Resulting regular expression: (?i)^[a-z]\d{6}$

Regex alpha1numeric6Pattern = new Regex(@"(?i)^[a-z]\d{6}$");

edited Mar 03 '15 at 13:51

answered Mar 03 '15 at 13:22

Mr. Polywhirl

It can be, I just wanted to let you know about the [modifiers](http://stackoverflow.com/a/3542048/1762224). – Mr. Polywhirl Mar 03 '15 at 13:39

score 1 · Answer 2 · answered Mar 03 '15 at 13:22

1

Try this:

^[a-zA-Z]\d{6}$

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answered Mar 03 '15 at 13:22

Bohemian

score 1 · Answer 3 · answered Mar 03 '15 at 13:22

1

This would do what you are after: ^[A-Za-z]\d{6}$. An example can be seen here.

answered Mar 03 '15 at 13:22

npinti

3 Answers3