How do I convert a Scala Double into a binary 64-bit String

Question

Basically I have a Double defined in Scala and I'd like it in a binary representation. For example:

val myDouble: Double = 0
val myDoubleAs64BitString = "00000000"+
                            "00000000"+
                            "00000000"+
                            "00000000"+
                            "00000000"+
                            "00000000"+
                            "00000000"+
                            "00000000"

This may sound and look crazy but basically for what I'm doing it's not. I'm basically writing a Chess application and I need a decent way of getting feedback while testing bitboard representations.

For everyone that read this, http://scala-exercises.47deg.com/index.html — Enrique Quero, Mar 03 '15 at 21:09
For a pure Java solution, you can check [this answer](http://stackoverflow.com/questions/6359847/convert-double-to-binary-representation). Also, it's worth noting that `myDouble` is an `Int` in this example. — resueman, Mar 03 '15 at 21:16
Thanks @resueman corrected. I'm a Java developer transitioning to Scala so unfamiliar with all the syntax just yet. — James Murphy, Mar 03 '15 at 21:27

score 8 · Accepted Answer · answered Mar 03 '15 at 21:42

8

The syntax in Scala is the same for this problem.

java.lang.Long.toBinaryString(java.lang.Double.doubleToRawLongBits(myDouble))

answered Mar 03 '15 at 21:42

Jonathan Crosmer

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How do I convert a Scala Double into a binary 64-bit String

1 Answers1