what is the difference between return and break in python? Please explain what they exactly do in loops and functions? thank you
6 Answers
break
is used to end a loop prematurely while return
is the keyword used to pass back a return value to the caller of the function. If it is used without an argument it simply ends the function and returns to where the code was executing previously.
There are situations where they can serve the same purpose but here are two examples to give you an idea of what they are used for
Using break
Iterating over a list of values and breaking when we've seen the number 3
.
def loop3():
for a in range(0,10):
print a
if a == 3:
# We found a three, let's stop looping
break
print "Found 3!"
loop3()
will produce the following output
0
1
2
3
Found 3!
Using return
Here is an example of how return
is used to return a value after the function has computed a value based on the incoming parameters:
def sum(a, b):
return a+b
s = sum(2, 3)
print s
Output:
5
Comparing the two
Now, in the first example, if there was nothing happening after the loop, we could just as well have used return
and "jumped out" of the function immediately. Compare the output with the first example when we use return
instead of break
:
def loop3():
for a in range(0, 6):
print a
if a == 3:
# We found a three, let's end the function and "go back"
return
print "Found 3!"
loop3()
Output
0
1
2
3

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break
is used to end loops while return
is used to end a function (and return a value).
There is also continue
as a means to proceed to next iteration without completing the current one.
return
can sometimes be used somewhat as a break when looping, an example would be a simple search function to search what
in lst
:
def search(lst, what):
for item in lst:
if item == what:
break
if item == what:
return item
And nicer, equivalent function, with return
:
def search(lst, what):
for item in lst:
if item == what:
return item # breaks loop
Read more about simple statements here.
At the instruction level you can see the statements do different things:
return
just returns a value (RETURN_VALUE
) to the caller:
>>> import dis
>>> def x():
... return
...
>>> dis.dis(x)
2 0 LOAD_CONST 0 (None)
3 RETURN_VALUE
break
stops a the current loop (BREAK_LOOP
) and moves on:
>>> def y():
... for i in range(10):
... break
...
>>> dis.dis(y)
2 0 SETUP_LOOP 21 (to 24)
3 LOAD_GLOBAL 0 (range)
6 LOAD_CONST 1 (10)
9 CALL_FUNCTION 1
12 GET_ITER
>> 13 FOR_ITER 7 (to 23)
16 STORE_FAST 0 (i)
3 19 BREAK_LOOP
20 JUMP_ABSOLUTE 13
>> 23 POP_BLOCK
>> 24 LOAD_CONST 0 (None)
27 RETURN_VALUE

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return
would finish the whole function while break
just make you finish the loop
Example:
def test_return()
for i in xrange(3):
if i==1:
print i
return i
print 'not able to reach here'
def test_break()
for i in xrange(3):
if i==1:
print i
break
print 'able to reach here'
test_return() # print: 0 1
test_break() # print: 0 1 'able to reach here'

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Return will exit the definition at the exact point that it is called, passing the variable after it directly out of the definition. Break will only cause the end of a loop that it is situated in.
For example
def Foo():
return 6
print("This never gets printed")
bar = Foo()
That will make bar equal to six. The code after the return statement will never be run.
The break example:
def Loop():
while True:
print("Hi")
break
Loop()
That will print only once, as the break statement will cause the end of the infinite while loop.

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Let's take a look at an example:
def f(x, y):
n = 0
for n in range(x, y):
if not n % 2: continue
elif not n % 3: break
return n
print((f(1, 10)))
This prints 3
. Why? Let's step through the program:
def f(x, y):
define a function
n = None
set variable 'n' to None
for n in range(x, y):
begin iterating from 'x' to 'y'. in our case, one through nine
if not n % 2: continue
discontinue this iteration if 'n' is evenly divisible by two
elif not n % 3: break
leave this iteration if n is evenly divisible by three
return n
our function 'f' "returns" the value of 'n'
print((f(1, 10)))
'f(1, 10)' prints three because it evaluates to 'n' once execution leaves the scope of the function

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I will try to illustrate it with an example:
def age_to_find_true_love(my_age):
for age in range(my_age, 100):
if find_true_love_at(age):
return age
if age > 50:
break
return "...actually do you like cats?"

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