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I have two lists of data.frames. Both lists have the same length and contain fitting data.frames in their according list elements. So the scenario looks like this

dfa = data.frame(a=1:3, b = letters[1:3])
dfb = data.frame(x=runif(3))
a = replicate(3, dfa, simplify = FALSE)
b = replicate(3, dfb, simplify = FALSE)

One obvious solution is:

lapply(seq_along(a), function(i) cbind(a[[i]], b[[i]]))

But I was wondering if their might be a better solution.

jakob-r
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2 Answers2

16

You can use Map

Map(cbind, a, b)
akrun
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4

You can use mapply : 

mapply(cbind, a, b, SIMPLIFY=F)
user1981275
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    `Map` is kind of a wrapper for `mapply(FUN = f, ..., SIMPLIFY = FALSE)` Check the `Map` – akrun Mar 06 '15 at 12:10