python 2.7.5 print one more '\n'

Question

cat t.py

import threading
import sys

class RecoverKey(threading.Thread):
    cond = threading.Condition()
    def __init__(self, idx=0):
        threading.Thread.__init__(self)
        self.idx = idx
    def run(self):
        for i in range(5):
            self.cond.acquire()
            print(self.idx * 10)
            sys.stdout.flush()
            self.idx *= 10
            self.cond.release()

if __name__ == '__main__':
    for i in range(1, 3):
        r = RecoverKey(i)
        r.start()

:~/test>python t.py 

10

20
100
200
1000
2000
10000
20000
100000
200000

Why there is one more line between '10' and '20'?

And sometime it may disappear..

This is interesting, I changed `3` to larger value and there's always one more line. — laike9m, Mar 06 '15 at 13:35
possible duplicate of [How do I get a thread safe print in Python 2.6?](http://stackoverflow.com/questions/3029816/how-do-i-get-a-thread-safe-print-in-python-2-6) — oefe, Mar 06 '15 at 15:49

score 0 · Answer 1 · edited May 23 '17 at 12:20

0

I would check out these two questions, which deal with the same issue. I'm not sure why it's happening, but it looks like replacing print x with print >> sys.stderr, x works (tried it).

edited May 23 '17 at 12:20

Community

1
1

answered Mar 06 '15 at 13:38

samGbos

867
1
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python 2.7.5 print one more '\n'

1 Answers1