how fade in a flex box?

Question

How do I get a flex box to not be part of the page until I fade it in? I used to do this with 'display: 0;' and then use jQuery .fadeIn(). But now if I set display to 0, when I fade it in, of course I lose the flex-iness of the box. If I use jQuery to set display to flex, then it will just appear, not fade in.

HTML

<div class="" id="popupContainer">
    <div class="flex-item-popup" id="popup">
        <div class="close"><i class="fa fa-2x fa-times-circle"></i></div>
        <h2></h2>
        <div class='text'></div>
        <div class="videos"></div>
        <div class="flex-container images"></div>
    </div>
</div>

CSS

#popupContainer {
    position: absolute;
    left: 0;
    top: 0;
    width: 100%;
    height: 100%;
    display:flex;
    flex-direction: row;
    flex-wrap: wrap;
    justify-content: center;
    align-content: flex-start;
    align-items: center;
    z-index: 15;
}

jQuery

$(document).ready(function() {
    //???
});

Very similar question, though related to `inline-block` it's the same underlying issue. I couldn't find one specific to `flex` so I won't close as duplicate. http://stackoverflow.com/questions/1091322/how-to-fade-to-display-inline-block — James Montagne, Mar 06 '15 at 20:21
You can set "display: flex" in the CSS and inline style="display: none" in HTML — Beamer, Mar 09 '18 at 10:15

score 145 · Accepted Answer · answered Mar 06 '15 at 20:04

It seems a bit odd, but what you can do is in the css, set it to display: none. Then the trick is to set the display to flex in your jquery and then hide it again, then fadeIn:

CSS:

#popupContainer {
    /* ... */

    display:none;
    flex-direction: row;
    flex-wrap: wrap;

    /* ... */
}

JS:

$("#popupContainer")
    .css("display", "flex")
    .hide()
    .fadeIn();

This works because fadeIn() will set the item back to its previous non-hidden display value. So setting flex and re-hiding it will set this "default" for it to be set back to.

http://jsfiddle.net/z2kxyjcq/1/

$("#popupContainer")
    .css("display", "flex")
    .hide()
    .fadeIn(2000);

#popupContainer {
    position: absolute;
    left: 0;
    top: 0;
    width: 100%;
    height: 100%;
    display:none;
    flex-direction: row;
    flex-wrap: wrap;
    justify-content: center;
    align-content: flex-start;
    align-items: center;
    z-index: 15;
    background-color: red;
}
#popupContainer *{
    border: 1px solid blue;
background-color: white;    
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="" id="popupContainer">
<div class="flex-item-popup" id="popup">
    <div class="close"><i class="fa fa-2x fa-times-circle">1</i></div>
    <h2>2</h2>
    <div class='text'>a</div>
    <div class="videos">b</div>
    <div class="flex-container images">c</div>
</div>

This works very good, also good to know, you can also do it in reverse when doing something like a hover behavior, on Hover: .css("display", "flex").hide().fadeIn(); and leaving: fadeOut().hide().css("display", "none"); — Lukas, Feb 24 '22 at 12:58

score 9 · Answer 2 · answered Nov 24 '17 at 15:56

Easiest and most clean way (if you can edit DOM) is to wrap the element, and fade the wrapper while having div with flex inside

<div class="popup" id="popupContainer">
  <div class="popup__flexbox">
    <div class="popup__flex-item" id="popup">
    <div class="popup__close">
       <i class="fa fa-2x fa-times-circle"></i>
    </div>
    <h2></h2>
    <div class='popup__text'></div>
    <div class="popup__videos"></div>
    <div class="popup__images"></div>
  </div>
</div>

css:

.popup {
  display: none;
}

.popup__flexbox {
  display: flex;
}

js:

$("#popupContainer").fadeIn();

score 5 · Answer 3 · answered Mar 06 '15 at 20:04

5

You can set the opacity as 0 and animate:

$('#popupContainer').animate({
    opacity: 1
}, 'fast');

answered Mar 06 '15 at 20:04

Lucas

339
1
7

1

This, while a good alternative would cause a big white space in your page since the box would still be in the document flow but just invisible ^.^ – SidOfc Oct 21 '15 at 09:14
This was the solution I was looking for. I could have an element already styled with `opacity: 0;` and then just animate it. No need to flip-flop on the display setting - that was causing glitching / flashing for me. – The Qodesmith Mar 01 '16 at 15:20
Some older versions of jQuery seem to set the display style in the `fadeTo` function, so I had to give up that shortcut and do it this way – brichins Jan 12 '17 at 19:07
If the content is appearing on top of another element you might have to add `visibility: hidden;` or `pointer-events: none;` – Lasithds Jul 28 '17 at 07:19
You probably don't want something like a conditional 'submit' button to just / be there / but be invisible. – sheriffderek Nov 25 '17 at 20:32

score 1 · Answer 4 · answered Aug 18 '17 at 08:04

var flex = $('#flex');

console.log(flex.css('display'));

flex.hide();

flex.velocity('fadeIn', {duration: 100, display: 'flex'});

setTimeout(function(){
  console.log(flex.css('display'));
 }, 100);

#flex{
  display: 'flex'
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/velocity/1.5.0/velocity.min.js"></script>

<div id="flex"></div>

score 1 · Answer 5 · answered Sep 11 '22 at 16:07

1

Best CSS only solution for fadeIn or jQuery show to display flex is that:

.fadeIn.fadeFlex[style*='display: block']{
    display: flex !important;
}

<div class="row fadeIn fadeFlex">
...
</div>

answered Sep 11 '22 at 16:07

Dangerdave

51
1
5

how fade in a flex box?

HTML

CSS

jQuery

5 Answers5

Linked