This Bash-only approach encapsulates all the timeout code inside your script by running a function as a background job to enforce the timeout:
#!/bin/bash
Timeout=1800 # 30 minutes
function timeout_monitor() {
sleep "$Timeout"
kill "$1"
}
# start the timeout monitor in
# background and pass the PID:
timeout_monitor "$$" &
Timeout_monitor_pid=$!
# <your script here>
# kill timeout monitor when terminating:
kill "$Timeout_monitor_pid"
Note that the function will be executed in a separate process. Therefore the PID of the monitored process ($$
) must be passed. I left out the usual parameter checking for the sake of brevity.