transfer file over udp

Question

I am trying to transfer file from a java client to a c# server over UDP. However, when i try to open the transfered file(png picture) on the server side it doesn't succeed open it. Someone please can help me?

The client code:(java)

import java.io.File;
import java.net.DatagramPacket;
import java.net.DatagramSocket;
import java.net.InetAddress;


public class Program {
    public static void main(String [] args)
    {
        DatagramSocket clientSocket;
        try {
            clientSocket = new DatagramSocket();

            InetAddress IPAddress = InetAddress.getByName("192.168.1.15");
            File myFile = new File ("D:/Users/user-pc/Downloads/phone.png");
            byte [] data  = new byte[(int)myFile.length()];
            DatagramPacket sendPacket = new DatagramPacket(data, data.length, IPAddress, 3109);
            clientSocket.send(sendPacket);
            clientSocket.close();
        } catch (Exception e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }
}

The server code:(c#)

using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Net;
using System.Net.Sockets;
using System.Text;
using System.Threading.Tasks;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            byte[] data;
            IPEndPoint ipep = new IPEndPoint(IPAddress.Any, 3109);
            UdpClient newsock = new UdpClient(ipep);
            IPEndPoint sender = new IPEndPoint(IPAddress.Any, 0);
            data = newsock.Receive(ref sender);
            File.WriteAllBytes(@"d:\pics\pic.png", data);
        }
    }
}

score 1 · Accepted Answer · edited May 23 '17 at 12:24

1

byte [] data  = new byte[(int)myFile.length()];

That is your problem, you just initialize a new byte array with the length of myFile. (not the actual data)

Here you can see how to convert your File to an actual Byte[]

(Files.toByteArray(File file))

edited May 23 '17 at 12:24

Community

1
1

answered Mar 09 '15 at 20:53

C1rdec

1,647
1
21
46

Thank you very much! i forgot to call the function that init the array with my file's bytes – Eyal Mar 09 '15 at 21:15

score 1 · Answer 2 · answered Mar 09 '15 at 21:00

First Before sending the picture, Decode it to a base64 string . A helper method here for encoding

public string ImageToBase64(Image image, System.Drawing.Imaging.ImageFormat format)
{
      using (MemoryStream stream = new MemoryStream())
   {
     // Convert Image to byte[]
    image.Save(stream , format);
    byte[] imageBytes = ms.ToArray();

    // Convert byte[] to Base64 String
    string base64String = Convert.ToBase64String(imageBytes);
    return base64String;
   }
}

Encode it into byte array and send it

    byte[] data = Encoding.ASCII.GetBytes(returnedStringFromEncoder);

Second : From the reciever side : convert the bytes array into string back

    string data = Encoding.ASCII.GetString(recievedByteArray);

Finally Convert it into a picture back

    public Image Base64ToImage(string base64String)
    {
      // Convert Base64 String to byte[]
      byte[] imageBytes = Convert.FromBase64String(base64String);
      MemoryStream stream = new MemoryStream(imageBytes, 0, 
      imageBytes.Length);

     // Convert byte[] to Image
     stream.Write(imageBytes, 0, imageBytes.Length);
     Image image = Image.FromStream(stream, true);
     return image;
   }

Base64 only makes sense if you're sending via a text-based protocol (e.g. HTTP). No need to use it in this case. — Ilian, Mar 09 '15 at 22:11

transfer file over udp

2 Answers2