Swift Array is printing word "optional" from my array dont want to force unwrap

Question

My array: var savedDataArray: Array<String>? = NSUserDefaults.standardUserDefaults().objectForKey("savedDataArray") as? Array<String>

console prints Optional(["75500.0", "2.19351e+08"]) I do not want the word "optional" or the braces

Force unwrapping var savedDataArray Array<String>! stops the word "optional" appearing however my array may be nil so dont I dont want to do this ( and the braces are still present)

This is not the same as the following answers as they all suggest foce unwrapping

Printing value of a optional variable includes the word "Optional" in Swift

How to print a string from plist without “Optional”?

Swift giving Optional(3) instead of 3 for .toInt

Actually many answers to the linked threads suggest *optional binding* and not *forced unwrapping* ... — Martin R, Mar 10 '15 at 18:00
Why do you want to avoid that? This will only be visible in log, but not in the end product — Christian, Mar 10 '15 at 18:00
@JSA986 But if you paste the values in a form or something like that, there shouldn't be an Optional — Christian, Mar 10 '15 at 18:05

score 4 · Answer 1 · answered Mar 11 '15 at 02:38

You can pass it to println as ImplicitlyUnwrappedOptional:

var array1:[String]? = ["foo", "bar"]
var array2:[String]? = nil

println(array1) // -> Optional(["foo", "bar"])
println(array2) // -> nil
println(array1 as [String]!) // -> [foo, bar]
println(array2 as [String]!) // -> nil

score 1 · Accepted Answer · answered Mar 10 '15 at 18:01

1

If you print out an optional, you will always have Optional(...) in there. The only way to lose that is to unwrap. That's the only solution.

If you are worried about nil values, check for nil and then unwrap.

answered Mar 10 '15 at 18:01

Sulthan

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That answers that then. Thanks – JSA986 Mar 10 '15 at 18:13

Yoichi Tagaya · Answer 3 · 2015-03-10T18:12:53.603

1

You can use ?? like this if it's ok to see no difference between nil and an empty array.

var array: [String]? = ["A", "B"]
println(array ?? []) // Prints "[A, B]"
array = nil
println(array ?? []) // Prints "[]"

edited Mar 10 '15 at 18:12

answered Mar 10 '15 at 18:03

Yoichi Tagaya

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score 0 · Answer 4 · answered Mar 10 '15 at 18:07

0

Its because it is an optional. You have to unwrap.

You can force unwrap:

println(myText!);

or check against a nil first

myText : String = myText ?? ""
println(myText)

answered Mar 10 '15 at 18:07

Michael Voznesensky

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Swift Array is printing word "optional" from my array dont want to force unwrap

4 Answers4