Adding char to an int without getting an incompatibility error

Question

I'm just learning that you can add an int to a char. I've tried out the following expecting it to compile, but I'm getting an incompatible types error:

char a = 'e' + (number / 10)

I can't figure out why, if

char c = '1'

I've seen that similar questions suggest the use of 'final' to resolve, but I've modified it to apply that and it still gets the same error.....

works then the above doesn't....

Any ideas?

`final` doesn't magically fix everything. Please read the duplicate carefully. `final` has the behavior of potentially making things constant expressions. — Sotirios Delimanolis, Mar 11 '15 at 04:43

score 1 · Accepted Answer · answered Mar 11 '15 at 04:42

1

This occurs because you need to cast the chars into ints before you can actually perform calculations with them: int answer = (int) 'e' + (number / 10) And then cast the answer back to a char:

answer = (char) answer

answered Mar 11 '15 at 04:42

Ittociwam

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Ah ok gotcha - so it would be char answer = (char) answer; ? – javapalava Mar 11 '15 at 04:49
Yes, this should work for what you are trying to do. – Ittociwam Mar 11 '15 at 05:17

Adding char to an int without getting an incompatibility error

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