PHP Exec is not working

Asked Mar 11 '15 at 06:16

Active Mar 11 '15 at 06:56

Viewed 852 times

I am trying to execute a .jar file from PHP. This is the code

$data = $cardnumber."|".$cvv."|".$expyear."|".$expmonth;
        $javacommand = "java -jar atomintegration.jar "."\"".$data."\"";
        echo "Command: ",$javacommand,"<br>";   
        exec($javacommand, $output);
        echo "Encrypted data: ",$output[0],"<br>";

It is just not working. Im using codeigniter. This function code is inside a library and the .jar file is also in the same dir as that of the library.

I tried running it from putty/shell it was executing.

In the code the exec is not working.

How do I resolve this?

edited Mar 11 '15 at 06:56

DavidPostill

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asked Mar 11 '15 at 06:16

Saritha Nair

What is the error output? – akhy Mar 11 '15 at 06:28
How can I see that ? There is no error being shown. – Saritha Nair Mar 11 '15 at 06:30
1

What version of PHP are you using? If you are using PHP 5.3.0 or less and safe mode is enabled, you can only execute files within the safe_mode_exec_dir – user3173104 Mar 11 '15 at 06:33
you can enable error reporting http://stackoverflow.com/a/5438125/670623 – akhy Mar 11 '15 at 06:34
This is turned on , but im not getting any errors. – Saritha Nair Mar 11 '15 at 06:35
do you have to try to exec `java -version`? could it print the output? if not, i think it's path problem. – bekt Mar 11 '15 at 06:40
possible duplicate of [PHP running java jar files with parameters as php variables](http://stackoverflow.com/questions/10004196/php-running-java-jar-files-with-parameters-as-php-variables) – bekt Mar 11 '15 at 06:43
Its printing the path and output of java version.. also my safe mode is off – Saritha Nair Mar 11 '15 at 07:13
can you try `exec('$javacommand 2>&1', $output); print_r($output);` to see what is response of your command. – user3173104 Mar 11 '15 at 08:14

PHP Exec is not working

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