cast String with period and comma to int

Question

how to cast String with period and comma to int, like

String a "9.000,00"
int b = Integer.parseInt(a);

when I run this code, I get an error message : Exception in thread "main" java.lang.NumberFormatException: For input string: "9.000,00"

Answer 1

If you want to get as result 900000 then simply remove all , and . and parse it with for instance with Integer.parseInt or Long.parseLong or maybe even better use BigInteger if number can be large.

String a = "9.000,00";
BigInteger bn = new BigInteger(a.replaceAll("[.,]", ""));
System.out.println(bn);

Output: 900000

---

But if you want to parse 9.000,00 into 9000 (where ,00 part is decimal fraction) then you can use NumberFormat with Locale.GERMANY which uses form similar to your input: 123.456,78

String a = "9.000,00";
NumberFormat format = NumberFormat.getInstance(Locale.GERMANY);
Number number = format.parse(a);
double value = number.doubleValue();
//or if you want int
int intValue = number.intValue();
System.out.println(value);
System.out.println(intValue);

Output:

9000.0
9000

Answer 2

final String a = "9.000,00";
final NumberFormat format = NumberFormat.getInstance(Locale.GERMAN); // Use German locale for number formats
final Number number = format.parse(a); // Parse the number
int i = number.intValue(); // Get the integer value

Reference

Answer 3

To do that, you need to use java.text.NumberFormat and NumberFormat.getInstance(Locale.FRANCE) (or another compatible Locale)

import java.text.NumberFormat;
import java.util.Locale;
class Test {
    public static void main(String[] args) throws Exception {
        NumberFormat format = NumberFormat.getInstance(Locale.FRANCE);
        String a = "9.000,00";
        a = a.replaceAll("\\.", "");
        Number number = format.parse(a);
        double d = number.doubleValue();
        int c = (int) Math.floor(d);   
        System.out.println(c);
    }
}

prints 9000 as you want ( and now is an int ) !

If I print every intermediate step :

import java.text.NumberFormat;
 import java.util.*;
class test {

public static void main(String[] args) throws Exception {
   NumberFormat format = NumberFormat.getInstance(Locale.FRANCE);
   String a = "9.000,00";
   a = a.replaceAll("\\.", "");
   System.out.println(a); // prints 9000,00
   Number number = format.parse(a);
   System.out.println(number); // prints 9000
   double d = number.doubleValue();
   System.out.println(d); // prints 9000.0
   int c = (int) Math.floor(d);   
   System.out.println(c); // prints 9000
}
}

so if Okem you want 9000,00 as you're saying in your comment, you just need

a = a.replaceAll("\\.", "");
System.out.println(a);

which gives you an output of 9000,00

I hope that helps.

Answer 4

Try this -

String a = "9.000,00";
a = a.replace(",","");
a = a.replace(".","");
int b = Integer.parseInt(a);

Answer 5

I think DecimalFormat.parse is the Java 7 API way to go:

String  a = "9.000,00";
DecimalFormat foo = new DecimalFormat();
Number bar = foo.parse(a, new ParsePosition(0));

After that, you go and be happy with the Number you just got.

If you want the answer to be 900000 (it doesn't make sense to me, but I'm replying to your question) and put that into an int go with:

int b = Integer.parseInt(a.replaceAll(",","").replaceAll("\\.",""));

as already outlined in the comments.