Remove specific parts from url

Question

Lets suppose I have a url like this:

https://www.youtube.com/watch/3e4345?v=rwmEkvPBG1s

What is the best and shorthest way to only get the 3e4345 part? Sometimes it doesn't contain additional params in ? I don't want to use any gems.

What I did was:

    url =  url.split('/watch/')
    url =  url[1].split('/')[0].split('?')[0]

Is there a better way? Thanks

score 1 · Answer 1 · answered Mar 11 '15 at 22:02

1

You could do the following and using the match function to find a match based on a regular expression statement. The value at [1] is the first capture from the regular expression. I have included a breakdown from regexper.com to help illustrate what the expression is accomplishing.

You will notice parentheses around the \d+ which are what captures the digits out of the URL when it matches.

url.to_s.match(/\/watch\/(\d+).*$/)[1]

Regexper

answered Mar 11 '15 at 22:02

Chris

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Perfect but the code can be also a string. But the code ends with `/` or `?` or with nothing for sure. So it could be: `wer34/hello` or `wer34/` or `wer34?locale=3` or `wer34`. Thanks for your help! – John Smith Mar 11 '15 at 22:06

score 1 · Accepted Answer · edited May 23 '17 at 12:06

1

possibly the safest and best one. use URI.

URI("https://www.youtube.com/watch/34345?v=rwmEkvPBG1s").path.split("/").last

For more refer How to extract URL parameters from a URL with Ruby or Rails?

edited May 23 '17 at 12:06

Community

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answered Mar 11 '15 at 22:08

Paritosh Piplewar

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score 1 · Answer 3 · answered Mar 11 '15 at 22:09

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x = "https://www.youtube.com/watch/34345?v=rwmEkvPBG1s"
File.basename(URI(x).path)
=> "34345"

answered Mar 11 '15 at 22:09

Mori

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Remove specific parts from url

3 Answers3