Handling signals in C after execl

Question

I have problem with handling signals. I run program in terminal, I am pressed CTRL + C, but don't see "I am pressed CTRL-C" wasn't printed. But I am trying delete row execl("/usr/bin/gedit", "gedit", "test.c", NULL), "I am pressed CTRL-C" was printed.

Can I help you, how to print "I am pressed CTRL-C" and explain why it is. I am appreciated of your help. Thank you very much.

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <signal.h>

int loop_forever = 1;

void on_sigint()
{
    printf("\nI am pressed CTRL-C\n");
    loop_forever = 0;
}

int main()
{
    printf("My homework\n");

    execl("/usr/bin/gedit", "gedit", "test.c", NULL);
    signal(SIGINT, on_sigint);
    while (loop_forever)
    {
    }

    exit(1);
}

score 2 · Accepted Answer · edited May 23 '17 at 11:59

2

execl executes another program in place of yours.

Basically, it transforms your process into a gedit process. Your code will no longer execute, and gedit will run in its place.

To run another program separate from yours, you can use

if(!fork()) {
  execl("/usr/bin/gedit", "gedit", "test.c", NULL);
}

See this question for a detailed description of how fork and exec works in the Unix process model.

edited May 23 '17 at 11:59

Community

1
1

answered Mar 13 '15 at 17:52

that other guy

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I am understanding that you said. Thank you very much. – Hoang Mar 13 '15 at 17:59

Handling signals in C after execl

1 Answers1