When I declare a variable of this incomplete type it compiles fine under clang:
int (* a)[]
But when I declare a function parameter of the same type it fails. Any rationale?
void func(int (*)[])
Life example.
It's the same in 'gcc' also.
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AnArrayOfFunctions
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http://stackoverflow.com/questions/20570857/pointer-to-array-of-unknown-bound – Gabriel Mar 15 '15 at 00:37
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I never find a good explanation there. They pointed out my first construction as illegal but it actually compiles. Also I'm comparing it's usage as a parameter and a variable declaration while the other one is describing the first case. – AnArrayOfFunctions Mar 15 '15 at 00:42
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I closed it as a duplicate of a different question. Please comment if you feel the answers there do not answer your question. Note: as pointed out there, although it's currently invalid to use such types as function parameters, it's being made legal and so should compile without issues in a future version of C++. – Mar 15 '15 at 00:51
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a successfully compiled program doesn't neccessarily be a legal program – phuclv Mar 15 '15 at 02:51