Open android application by click on website button?

Question

I have android application which contain html webpage with one single button. The html file is placed into the asset folder in android. I open html file into the webview. Now, i what want to open the another application which is install in android device by click on the html page button.

Can you please anyone help me how i will do that and also give me the some reference from where i will get some help?

http://stackoverflow.com/questions/2780102/open-another-application-from-your-own-intent or try this `Intent launchIntent = getPackageManager().getLaunchIntentForPackage("com.package.address"); startActivity(launchIntent);` — Apurva, Mar 16 '15 at 19:43
This is work for me [1]: http://stackoverflow.com/a/2958870/3758898 — Kishan Vaghela, Mar 16 '15 at 19:48

score 2 · Answer 1 · answered Mar 16 '15 at 19:54

2

I think @Sk Maniruddin is asking how to open another app from a webpage. And the solution to that is using an intent, as the link.

  <a href="intent://scan/#Intent;scheme=zxing;package=com.google.zxing.client.android;end"> Take a QR code </a>

for more information you can look at the doc: https://developer.chrome.com/multidevice/android/intents#example

answered Mar 16 '15 at 19:54

kaho

4,746
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Yes, I am asking this. But using this link the app is not open. – Sk Maniruddin Mar 16 '15 at 20:13
Hum.. it works for me. Are you using something like `myWebView.setWebViewClient(new WebViewClient());` to force the new link open in the same page? – kaho Mar 16 '15 at 20:21
I am use like that you have mention. – Sk Maniruddin Mar 16 '15 at 20:28
oh.. then you should disable/delete it, otherwise this would not work. – kaho Mar 16 '15 at 20:33
I don't think you need anything. not even the `` if you are using a local file – kaho Mar 16 '15 at 20:40
Click Me write in html file. – Sk Maniruddin Mar 16 '15 at 20:41
Write in manifest file. Is there any think wrong? – Sk Maniruddin Mar 16 '15 at 20:42

score 0 · Answer 2 · answered Mar 16 '15 at 20:08

0

Firstly set your onclik method of button in html like this.

<input type="submit" name="submit" id="submit_id" onclick="click.performClick();" />

enable javascript your webview

webView.getSettings().setJavaScriptEnabled(true);

after that you can detect this click by this code:

webView.addJavascriptInterface(new Object() {
            @JavascriptInterface
            public void performClick() {// detected click 
                Intent i = new Intent(FromActivity.This, DestinationActivity.class);
                    startActivity(i);

            }

        }, "click");

answered Mar 16 '15 at 20:08

Cüneyt

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interesting. I used this method on my 2 projects and it was work. Are you sure to make evrything correctly? Did you notice the name that before ?.performClick(); must be same with the end of the addJavascriptInterface method's parameter? – Cüneyt Mar 16 '15 at 20:43
webview.getSettings().setJavaScriptEnabled(true); webview.loadUrl("file:///android_asset/index.html"); webview.addJavascriptInterface(new Object() { @JavascriptInterface public void performClick() {// detected click // Intent i = new Intent(FromActivity.This, DestinationActivity.class); // startActivity(i); Toast.makeText (MainActivity.this, "Hello", Toast.LENGTH_SHORT).show(); } }, "click"); I write the above code. – Sk Maniruddin Mar 16 '15 at 20:47
Did you set click method of button in html like this? onclick="click.performClick();" – Cüneyt Mar 16 '15 at 20:50
Yes. I use same method. – Sk Maniruddin Mar 16 '15 at 20:52
03-17 02:23:16.901: I/chromium(16994): [INFO:CONSOLE(12)] "Uncaught TypeError: undefined is not a function", source: file:///android_asset/index.html (12) I got message like above. – Sk Maniruddin Mar 16 '15 at 20:53
Can you try webview.getSettings().setDomStorageEnabled(true); – Cüneyt Mar 16 '15 at 20:58
I throw in the towel :) I hope you will find the solution. Have a nice day. – Cüneyt Mar 16 '15 at 21:05

Open android application by click on website button?

2 Answers2