Is there any way to wait 10 seconds and then execute the next line of code in Java?

Question

In my program, I try to find a css address then I do some other computations. I need to execute the next line of my code if FolderTest1 is null.

WebElement FolderTest1 = driverChrome.findElement(By.cssSelector("#nav-51846c7840975f97241367"));
driverChrome.manage().timeouts().implicitlyWait(10,TimeUnit.SECONDS);

Thanks

Your question is confusing, but to answer your *title*, yes, just put `try { Thread.sleep(10000); } catch (InterruptedException e1) { e1.printStackTrace(); }` before the line. — Shashank, Mar 18 '15 at 21:08
possible duplicate of [How can I delay a Java program for a few seconds?](http://stackoverflow.com/questions/3342651/how-can-i-delay-a-java-program-for-a-few-seconds) — Artemis, Mar 18 '15 at 21:11

score 0 · Answer 1 · answered Mar 18 '15 at 21:34

0

Something like this?

WebElement FolderTest1 = driverChrome.findElement(By.cssSelector("#nav-51846c7840975f97241367"));
if(FolderTest1 == null)
{
    try
    {
        Thread.sleep(10000);
    }
    catch(InterruptedException ie)
    {}    
}

answered Mar 18 '15 at 21:34

preston.m.price

646
1
10
17

no. In first line, if the program couldn't find the css address it does not do anything!! – Hoomii Mar 18 '15 at 21:38
I mean, I want to execute the rest of the code after 10 seconds, with or without finding css address. – Hoomii Mar 18 '15 at 21:39

Is there any way to wait 10 seconds and then execute the next line of code in Java?

1 Answers1