Pattern match to get string between brackets

Question

I am trying to find whatever string is in between the aggregate() and find(). Below is my code.

var str1 = 'aggregate([{$group:{_id:{state:"$state",city:"$city"},sum:{$sum:"$pop"}}},{$sort:{sum:1}},{$group:{_id:"$_id.state",smallestcity:{$first:"$_id.city"},smallest:{$first:"$sum"},largestcity:{$last:"$_id.city"},largest:{$last:"$sum"}}}])'
var str2 = 'find({awards:{$elemMatch:{award:"Turing Award",year:{$gt:1980}}}}).limit(0)'

var matchPharse = /((.*))/;
var result = str1.match(matchPharse);
console.log(result);

I am getting the result always the whole string instead of

[{$group:{_id:{state:"$state",city:"$city"},sum:{$sum:"$pop"}}},{$sort:{sum:1}},{$group:{_id:"$_id.state",smallestcity:{$first:"$_id.city"},smallest:{$first:"$sum"},largestcity:{$last:"$_id.city"},largest:{$last:"$sum"}}}]

I am searching for something like this

@AvinashRaj I think OP posted the expected output after "instead of" — bozdoz, Mar 19 '15 at 07:35

score 1 · Answer 1 · answered Mar 19 '15 at 07:32

1

try this pattern instead:

var matchPharse = /((\[.*\]))/;

answered Mar 19 '15 at 07:32

mish

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score 1 · Answer 2 · answered Mar 19 '15 at 07:35

1

((\[.*?\]))

You Should use a non greedy expression.

answered Mar 19 '15 at 07:35

vks

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score 1 · Answer 3 · answered Mar 19 '15 at 07:43

1

Try the following RegEx:

var matchPharse= /\((.*)\)/g;

Matches any sequence between ().

This is a DEMO.

var str1 = 'aggregate([{$group:{_id:{state:"$state",city:"$city"},sum:{$sum:"$pop"}}},{$sort:{sum:1}},{$group:{_id:"$_id.state",smallestcity:{$first:"$_id.city"},smallest:{$first:"$sum"},largestcity:{$last:"$_id.city"},largest:{$last:"$sum"}}}])'
var str2 = 'find({awards:{$elemMatch:{award:"Turing Award",year:{$gt:1980}}}}).limit(0)'
var matchPharse = /\((.*)\)/;
var result = str1.match(matchPharse);
alert(result);

answered Mar 19 '15 at 07:43

cнŝdk

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Please correct me if I am doing something wrong in the below split. Im splitting on }, var str = '{"a": 2000, "b": "sam"},{"c":1,"d":1}' var res = str.split(/(?:\}\,|\,\{)/); console.log(res[0]) //'{"a": 2000, "b": "sam"' - One bracket is missing console.log(res[1]) //'{"c":1,"d":1}' Expecting output res[0] = {"a": 2000, "b": "sam"} – user4324324 Mar 19 '15 at 12:27
if you use split() on } the `}` will not count in the splitted strings. – cнŝdk Mar 19 '15 at 13:35

score 0 · Answer 4 · answered Mar 19 '15 at 07:33

0

You just need to escape the outside parentheses. Try:

var matchPharse = /\((.*)\)/;

For just the content inside the parentheses use result[1]

answered Mar 19 '15 at 07:33

bozdoz

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that would include the parentheses – mish Mar 19 '15 at 07:34

Pattern match to get string between brackets

4 Answers4