Differences of float in python2 and python3?

Question

I wrote those simple lines and run them on python 2/3.

i=1.194857193845710948754654
print(len(str(i)))

I got 2 different outputs. What is the reason for that? and how could I achieve the same output in python2 ?

Output python2:

>>> 13

Output python3:

>>> 18

Take a look at [Floating Point Numbers](http://stackoverflow.com/q/20473968/4014959) — PM 2Ring, Mar 21 '15 at 13:55

score 3 · Answer 1 · answered Mar 21 '15 at 13:46

3

It's because of different implementation of str() for float, as can easily be verified.

The actual float precision is the same.

$ python2
Python 2.7.9
>>> i=1.194857193845710948754654
>>> i
1.1948571938457109
>>> str(i)
'1.19485719385'
>>>

$ python3
Python 3.4.3
>>> i=1.194857193845710948754654
>>> i
1.1948571938457109
>>> str(i)
'1.1948571938457109'
>>>

answered Mar 21 '15 at 13:46

MightyPork

thanks a lot, this solved my problem. I didnt thought the string conversion could be the limiting factor :) – fu2y Mar 21 '15 at 13:53

1 Answers1