Why does parseInt() return a wrong integer?

Asked Mar 22 '15 at 00:22

Active Mar 22 '15 at 00:22

Viewed 44 times

I can't seem to understand why parseInt() returns a wrong result when I parse 1329879643513216515489679841651614 like this:

parseInt(1329879643513216515489679841651614);//supposed to return the number yet returns 1

and how can I parse that number as a full number please?

asked Mar 22 '15 at 00:22

Naturious

1

http://www.2ality.com/2012/07/large-integers.html – user229044 Mar 22 '15 at 00:26
JS can't count that high, so why do you need to? – dandavis Mar 22 '15 at 00:47
2

There is no point in passing a number to `parseInt`. If you used the string `"1329879643513216515489679841651614"`, you would get `1.3298796435132165e+33`, which makes more sense than `1`. – Oriol Mar 22 '15 at 00:55

0 Answers0