PHP shell_exec will not run ls

Question

I am running the following php script:

<?php

ini_set('display_errors', 'On');
error_reporting(E_ALL);

date_default_timezone_set('UTC');

echo nl2br("Before\n\n");

$out = shell_exec("ls -lart");
echo "<pre>$out</pre>";

echo nl2br("After\n\n");


?>

I cannot get shell_exec or exec to work at all. The script above produces:

Before
After

but nothing in between.

Is ls on the $PATH? Does the uid have a shell? Is php running chroot? — symcbean, Mar 23 '15 at 23:34
What does "uid have a shell" mean? And what is chroot. Could you explain further please — ManInMoon, Mar 24 '15 at 09:24
Here hou have (robust) function http://stackoverflow.com/a/12980534/3896852 — hubertinio, Mar 24 '15 at 13:39

score 0 · Answer 1 · answered Mar 24 '15 at 13:34

I think shell_exec function is disabled in your php.ini . You can check it by

if(function_exists('shell_exec')) {
    echo "shell_exec is enabled";
} else {
    echo "shell_exec is disabled";
}

Open your php.ini and navigate to section disable_functions

If shell_exec is listed under there , remove it.

Then restart apache / php handler.

Also If Safe Mode is enabled this function will not be available. You need to disable it.

PHP shell_exec will not run ls

1 Answers1