the kind of distance you ask is not included in levenshtein - but you should use a helper like euclidean or manhattan distance, to get the result.my simple assumption is, q (in english qwerty layout) is cartesian (y=0; x=0)
so, w will be (y=0; x=1) and so on. whole list here
keyboard_cartesian= {
'q': {'y': 0, 'x': 0},
'w': {'y': 0, 'x': 1},
'e': {'y': 0, 'x': 2},
'r': {'y': 0, 'x': 3},
# ...
'a': {'y': 1, 'x': 0},
#...
'z': {'y': 2, 'x': 0},
'x' : {'x':1, 'y':2},
#
}
assume, word qaz has a meaning.
levenshtein distance between qaz
and with both of waz
and eaz
is 1. to check out which misspell is more likely, take the differences (here (q,w) and (q,e)) and calculate euclidean distance
>>> from math import *
>>> def euclidean_distance(a,b):
... X = (keyboard_cartesian[a]['x']-keyboard_cartesian[b]['x'])**2
... Y = (keyboard_cartesian[a]['y']-keyboard_cartesian[b]['y'])**2
... return sqrt(X+Y)
...
>>> euclidean_distance('q', 'w')
1.0
>>> euclidean_distance('q', 'e')
2.0
this means misspell of qaz as waz is more likley than qaz as eaz.