Java - Add numbers to matching words

Question

I'm trying to add a count number for matching words, like this:

Match word: "Text"

Input: Text Text Text TextText ExampleText

Output: Text1 Text2 Text3 Text4Text5 ExampleText6

I have tried this:

String text = "Text Text Text TextText ExampleText";
String match = "Text";
int i = 0;
while(text.indexOf(match)!=-1) {
text = text.replaceFirst(match, match + i++);
}

Doesn't work because it would loop forever, the match stays in the string and IndexOf will never stop.

What would you suggest me to do? Is there a better way doing this?

Consider using two strings, one for original data and one for modified. Possible improvements: use StringBuilder, use regex expressions. — S. Pauk, Mar 25 '15 at 08:18
create a second String, in which you write the parts you have already "adjusted". Then, remove it from the original String, so that the while indexof will eventually return -1 — Stultuske, Mar 25 '15 at 08:19
http://stackoverflow.com/questions/767759/occurrences-of-substring-in-a-string Might help — seenukarthi, Mar 25 '15 at 08:20

score 2 · Accepted Answer · answered Mar 25 '15 at 08:50

2

Here is one with a StringBuilder but no need to split:

public static String replaceWithNumbers( String text, String match ) {
    int matchLength = match.length();
    StringBuilder sb = new StringBuilder( text );

    int index = 0;
    int i = 1;
    while ( ( index = sb.indexOf( match, index )) != -1 ) {
        String iStr = String.valueOf(i++);
        sb.insert( index + matchLength, iStr );

        // Continue searching from the end of the inserted text
        index += matchLength + iStr.length();
    }

    return sb.toString();
}

answered Mar 25 '15 at 08:50

RealSkeptic

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Cool. It looks like my solution. ;-) – SubOptimal Mar 25 '15 at 08:52
@SubOptimal Could be. I've been testing it before I posted, you may have posted earlier. BTW, have you tested your code when the string to match is a digit? – RealSkeptic Mar 25 '15 at 09:08

score 2 · Answer 2 · answered Mar 25 '15 at 09:29

first take one stringbuffer i.e. result,Then spilt the source with the match(destination). It results in an array of blanks and remaining words except "Text". then check condition for isempty and depending on that replace the array position.

String text = "Text Text Text TextText ExampleText";
    String match = "Text";
    StringBuffer result = new StringBuffer();
    String[] split = text.split(match);
    for(int i=0;i<split.length;){
        if(split[i].isEmpty())
            result.append(match+ ++i);
        else
            result.append(split[i]+match+ ++i);
    }
    System.out.println("Result is =>"+result);

O/P Result is => Text1 Text2 Text3 Text4Text5 ExampleText6

Hamza Alayed · Answer 3 · 2015-03-25T08:58:07.643

1

Try this solution is tested

    String text = "Text Text Text TextText Example";
    String match = "Text";
    String lastWord=text.substring(text.length() -match.length());

    boolean lastChar=(lastWord.equals(match));

    String[] splitter=text.split(match);
    StringBuilder sb = new StringBuilder();
    for(int i=0;i<splitter.length;i++)
    {

       if(i!=splitter.length-1)
           splitter[i]=splitter[i]+match+Integer.toString(i);
       else
          splitter[i]=(lastChar)?splitter[i]+match+Integer.toString(i):splitter[i];

       sb.append(splitter[i]);
       if (i != splitter.length - 1) {
           sb.append("");
       }
    }
    String joined = sb.toString();
    System.out.print(joined+"\n");

edited Mar 25 '15 at 08:58

answered Mar 25 '15 at 08:23

Hamza Alayed

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please give me new text you test it. to check fix the issue – Hamza Alayed Mar 25 '15 at 08:37
@DeveloperH Use for example `text = "Text Text Text TextText ExampleTex"` and the `match = "Text"` the result is `Text0 Text1 Text2 Text3Text4 ExampleTexText5`. Use my solution and it works. ;-) – SubOptimal Mar 25 '15 at 08:50
I just finished the issue. – Hamza Alayed Mar 25 '15 at 08:59

SubOptimal · Answer 4 · 2015-03-25T09:15:10.560

One possible solution could be

String text = "Text Text Text TextText ExampleText";
String match = "Text";
StringBuilder sb = new StringBuilder(text);
int occurence = 1;
int offset = 0;
while ((offset = sb.indexOf(match, offset)) != -1) {
    // fixed this after comment from @RealSkeptic
    String insertOccurence = Integer.toString(occurence);
    sb.insert(offset + match.length(), insertOccurence);
    offset += match.length() + insertOccurence.length();
    occurence++;
}
System.out.println("result: " + sb.toString());

TheLostMind · Answer 5 · 2015-03-25T08:27:52.903

0

This will work for you :

public static void main(String[] args) {
    String s = "Text Text Text TextText ExampleText";
    int count=0;
    while(s.contains("Text")){
        s=s.replaceFirst("Text", "*"+ ++count); // replace each occurrence of "Text" with some place holder which is not in your main String.
    }
    s=s.replace("*","Text");
    System.out.println(s);


}

O/P:

Text1 Text2 Text3 Text4Text5 ExampleText6

edited Mar 25 '15 at 08:27

answered Mar 25 '15 at 08:26

TheLostMind

35,966
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2

What if there will be * in text ? you should use another sign like Bell character or smth. – Milkmaid Mar 25 '15 at 08:27
@Milkmaid - I was editing my answer.. You have to choose something which is not present in the string – TheLostMind Mar 25 '15 at 08:28

score 0 · Answer 6 · answered Mar 25 '15 at 08:34

I refactored @DeveloperH 's code to this:

public class Snippet {

    public static void main(String[] args) {
        String matchWord = "Text";
        String input = "Text Text Text TextText ExampleText";
        String output = addNumbersToMatchingWords(matchWord, input);
        System.out.print(output);
    }

    private static String addNumbersToMatchingWords(String matchWord, String input) {
        String[] inputsParts = input.split(matchWord);

        StringBuilder outputBuilder = new StringBuilder();
        int i = 0;
        for (String inputPart : inputsParts) {
            outputBuilder.append(inputPart);
            outputBuilder.append(matchWord);
            outputBuilder.append(i);
            if (i != inputsParts.length - 1)
                outputBuilder.append(" ");
            i++;
        }
        return outputBuilder.toString();
    }
}

Nice work. I edit my answer. please check my answer then edit it yours — Hamza Alayed, Mar 25 '15 at 09:05

score 0 · Answer 7 · answered Mar 25 '15 at 11:35

We can solve this by using stringbuilder, it provides simplest construct to insert character in a string. Following is the code

    String text = "Text Text Text TextText ExampleText";
    String match = "Text";
    StringBuilder sb = new StringBuilder(text);
    int beginIndex = 0, i =0;
    int matchLength = match.length();
    while((beginIndex = sb.indexOf(match, beginIndex))!=-1) {
         i++;
         sb.insert(beginIndex+matchLength, i);
         beginIndex++;
    }
    System.out.println(sb.toString());

Java - Add numbers to matching words

7 Answers7