How to extract array entries for method call in python

Question

I have an array that should be expanded to provide multiple arguments to a function call - like the following:

def x(a,b,c):
    print "%d %d %d" %(a,b,c)

t = [1,2,3]

x(t[:])  # Will not work - this is only one value

Basically I am looking for the python equivalent to the

:_*

construct in scala

possible duplicate of [Python - use list as function parameters](http://stackoverflow.com/questions/4979542/python-use-list-as-function-parameters) — jkd, Mar 25 '15 at 23:20

score 9 · Accepted Answer · answered Mar 25 '15 at 23:17

9

It's called unpacking:

>>> def x(a, b, c):
...     print(a, b, c)
...
>>> l = [1, 2, 3]
>>> x(*l)
(1, 2, 3)

answered Mar 25 '15 at 23:17

Celeo

score 2 · Answer 2 · answered Mar 25 '15 at 23:34

2

In addition to unpacking, you can change your function to accept a list:

def x(nums):
    # cut off list and join three elements
    print ' '.join(str(i) for i in nums[:3])

answered Mar 25 '15 at 23:34

Malik Brahimi

2 Answers2