Using R lapply on a list to remove elements from the list

Question

I have a list I want to process to remove elements not meeting certain criteria. I'd use a loop but that is too slow so I assume lapply might be better.

assuming the last thing function y does is give a value of 1 or 2 to variable x how would I modify

lapply(list,functiony, z=valueA, a=valueB) to give back a list of only the elements of the list that are of value x=1?

Please show some example data and your expected results. It is not clear what `functiony` is. http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example — akrun, Mar 26 '15 at 09:07
Maybe you could start showing us how you would proceed with a loop tp clarify what you want to do? — Dominic Comtois, Mar 26 '15 at 09:17

score 3 · Answer 1 · answered Mar 26 '15 at 09:27

3

Try mylist[sapply(mylist, functiony, z=valueA, a=valueB)==1]

answered Mar 26 '15 at 09:27

Rufo

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Using R lapply on a list to remove elements from the list

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