Understanding uart byte period with start bit, parity bit, and stop bit

Question

I want to know how many bytes are transmitted in the second with some specicifc baud rate. IE, for example, I have a baudrate=9600, so I can send

9600 / 8 = 1200

bytes per second.

So, how much uart bytes can I send with 8bit + 1 stop bit + 1 parity bit? Does it equal to

9600 / 10 = 960

?

score 1 · Accepted Answer · answered Mar 26 '15 at 23:23

1

You forgot the start bit, it is 9600 / (1 + 8 + 1 + 1) = 872.

answered Mar 26 '15 at 23:23

Hans Passant

Does a start bit supported by a driver? – Alex Antonov Mar 26 '15 at 23:24
Not sure I can decode that comment. Only the UART ever sees the start bit, the driver is not involved and there's no configuration for it. – Hans Passant Mar 26 '15 at 23:27
Thanks for answer! Please wait while I make another question :D – Alex Antonov Mar 26 '15 at 23:35
http://stackoverflow.com/questions/29290866/9-bits-uart-emulation-with-dev-tty that's it – Alex Antonov Mar 26 '15 at 23:40

1 Answers1