How rounded decimal 2

Question

How rounded decimal 2?

48382,06 + 86106,62 + 83650,07 + 72939,61 = 291078,36

NSNumber *returnSum = 0;

for (int i = 0; i < [arraySum count]; i++) {
        PayDoc *payDoc = (PayDoc*)([arraySum objectAtIndex:i]);
        returnSum = [NSNumber numberWithFloat:[returnSum floatValue]+[payDoc.SOBTR floatValue]];
    }

Answer result my code returnSum = 291078,38

possible duplicate of [Make a float only show two decimal places](http://stackoverflow.com/questions/560517/make-a-float-only-show-two-decimal-places) — Burhanuddin Sunelwala, Mar 30 '15 at 10:35
from where are you getting values for sum?? from string or else where? — Saurabh Prajapati, Mar 30 '15 at 10:50

Burhanuddin Sunelwala · Accepted Answer · 2015-03-30T11:30:04.137

Use NSDecimalNumber. Set scale to 2 and roundingMode to NSRoundPlain

NSDecimalNumber *returnSum = [[NSDecimalNumber alloc] initWithFloat:0.0f];

for (PayDoc *payDoc in arraySum) {

        NSDecimalNumber *sobtr = [[NSDecimalNumber alloc] initWithFloat:payDoc.SOBTR.floatValue];
        returnSum = [returnSum decimalNumberByAdding:sobtr withBehavior:[NSDecimalNumberHandler decimalNumberHandlerWithRoundingMode:NSRoundPlain scale:2 raiseOnExactness:YES raiseOnOverflow:YES raiseOnUnderflow:YES raiseOnDivideByZero:YES]];
}

I tested the above values and it gives 291078.36

luk2302 · Answer 2 · 2015-03-30T11:04:42.290

1

Have you tried the following?

returnSum = @(  roundf([returnSum floatValue] * 100) / 100 + roundf([payDoc.SOBTR floatValue] * 100) / 100  );

That will cause the float to only have two digits (approximately...) after the decimal point, not to just show two digits as the other comments and answers suggest.

Alternatively if you dont want to round the floats and just want to strip off the decimal digits you can write

returnSum = @(  (int)([returnSum floatValue] * 100) / 100.0 + (int)([payDoc.SOBTR floatValue] * 100) / 100.0  );

edited Mar 30 '15 at 11:04

answered Mar 30 '15 at 10:56

luk2302

55,258
23
97
137

returnSum = @ (roundf ([returnSum floatValue] * 100) / 100 + roundf ([payDoc.SOBTR floatValue] * 100) / 100); 291078,38 – Valeriy Mar 30 '15 at 11:03
sorry, forgot an `n` in `roundf` – luk2302 Mar 30 '15 at 11:04

score 0 · Answer 3 · answered Mar 30 '15 at 10:31

0

Use [NSNumber numberWithInt:[returnSum floatValue]+[payDoc.SOBTR floatValue]];

answered Mar 30 '15 at 10:31

Sanjay Mohnani

5,947
30
46

I need 291078,36! Your method 291078,00. – Valeriy Mar 30 '15 at 10:35
you can use @"%.2f" = 3145.56 as NSString* number = [NSString stringWithFormat:@"%.2f", floatNumber]; – Sanjay Mohnani Mar 30 '15 at 10:42

score -1 · Answer 4 · answered Mar 30 '15 at 11:02

The best to do this is the following:

NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];

[formatter setNumberStyle:NSNumberFormatterDecimalStyle];
[formatter setMaximumFractionDigits:2];
[formatter setRoundingMode: NSNumberFormatterRoundUp];

NSString *numberString = [formatter stringFromNumber:[NSNumber numberWithFloat:[returnSum floatValue]+[payDoc.SOBTR floatValue]]];

NSLog(@"Result...%@",numberString);

How rounded decimal 2

4 Answers4