preg_replace - only URL which is starting from "http" and ending by ".flv"

Question

I'm trying to create an replacement which remove everything what is not between "http://" and ".flv".

Here is my code:

preg_replace('"http://(.*?).f;v"', '', $code);

but it doesn't work. Anyone can help me?

Thanks.

Also this will remove everything that starts with http:// and ends with flv and you wrote "not between". You need to escape dot before flv too (\.flv). As @Rizier123 mentioned, your delimiters are wrong. And why don't just preg_match_all to this pattern and collect matching values? You can implode them if you need them in one string. — BlindingLight, Mar 30 '15 at 14:04

Drakes · Answer 1 · 2015-03-30T14:20:48.870

1

remove everything what is not between "http://" and ".flv"

http://example.com/path/test.flv?param=1 --> example.com/path/test

BTW, you have a typo in f;v, and your delimiters may cause problems. Replace

preg_replace('"http://(.*?).f;v"', '', $code);

with

preg_replace('/http\:\/\/(.*?)\.flv.*/i', '$1', $code);

edited Mar 30 '15 at 14:20

answered Mar 30 '15 at 14:01

Drakes

Does it work? Does it remove *everything what is not between "http://" and ".flv"*? – tmt Mar 30 '15 at 14:05
Do you mean you want to keep the domain and path? – Drakes Mar 30 '15 at 14:05
That's what Newester specified, not me. :-) – tmt Mar 30 '15 at 14:06
1

He said *what is NOT between* which IMHO means remove everything but keep this sort of URLs intact. But I guess you better wait for his confirmation. – tmt Mar 30 '15 at 14:13
I'm on the same page as you @cascaval. I've updated my answer, but let's wait for the OP to respond – Drakes Mar 30 '15 at 14:15
@Newster Hello, was this indeed what you wanted as a solution? – Drakes Apr 22 '15 at 23:28

score 0 · Answer 2 · answered Mar 30 '15 at 13:59

0

Are you looking for something like this:

http:\/\/(.*?).flv

http://www.somesite.com/ac.flv

answered Mar 30 '15 at 13:59

Keep Coding

2 Answers2