How to set a variable in a Makefile to a filename via a file pattern, only if the pattern has ONE match

Question

I have a makefile for GNU make to build documents from markdown text files. The makefile has a variable INPUT I want to set to the filename of the markdown file. All markdown files follow the pattern *.md.

However I want set INPUT only to the filename when there is only one file matching the pattern, if there are more than one markdown file, make should exit with an error.

I tried the obvious choice

INPUT ?= *.md

but this sets INPUT of course to a list of **all* matches. So it works correctly for a directory which contains, say, only file_a.md, but in a directory with

file_a.md
file_b.md

INPUT contains afterwards "file_a.md file_b.md", which messes up my rules expecting INPUT to contain one file or to exit.

Any way to assign INPUT as I want to with makefile syntax?

What do you want to be assigned to `INPUT` if there is more than one file? Nothing? Do you want make to throw an error? — Etan Reisner, Mar 30 '15 at 23:04
Yes, If there is more than one match I want `make` to exit with an error. — halloleo, Mar 30 '15 at 23:08

score 3 · Accepted Answer · answered Mar 30 '15 at 23:22

3

To do what you want you need to use the $(wildcard) function to force the globbing to be done immediately (otherwise make will wait until the variable is used in an appropriate place before expanding the glob).

INPUT ?= $(wildcard *.md)

ifneq (1,$(words $(INPUT)))
    $(error Too many or two few input files found.)
endif

answered Mar 30 '15 at 23:22

Etan Reisner

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Great idea to use the `wildcard` function. That's what I was missing. Thx! – halloleo Mar 31 '15 at 08:03

How to set a variable in a Makefile to a filename via a file pattern, only if the pattern has ONE match

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