How can i find all digits in a string using regexps in python

Question

Hello iam trying to find all the degits in a string but it returns an empty list

my code :

import re
re.findall(r'/d','5585858')
>>>> []

what is the error please ?

That's good too, although I prefer to check whether a character is a digit with `isdigit()`. — TigerhawkT3, Apr 01 '15 at 07:53

Mazdak · Accepted Answer · 2015-04-01T07:53:01.090

2

You have a wrong pattern, you need \d first and for get all of digits you can add + to \d for match 1 or more combine of digits :

re.findall(r'\d+','5585858')

Also based on your string you can use other functions like re.search that may be more efficient.

And if you want to convert your string to list you can simply use list :

>>> list('5585858')
['5', '5', '8', '5', '8', '5', '8']

edited Apr 01 '15 at 07:53

answered Apr 01 '15 at 07:46

Mazdak

score 1 · Answer 2 · answered Apr 01 '15 at 07:48

1

use '\d+' instead of '/d'

 >>> import re
 >>> re.findall(r'\d+', '5585858')
 ['5585858']

answered Apr 01 '15 at 07:48

Dyrandz Famador

score 0 · Answer 3 · answered Apr 01 '15 at 07:48

0

You don't even need a regular expression for that.

>>> [number for number in '5585a858' if number.isdigit()]
['5', '5', '8', '5', '8', '5', '8']

answered Apr 01 '15 at 07:48

TigerhawkT3

3 Answers3