How to split string without spaces into list of integers in Python?

Question

I take a string of integers as input and there are no spaces or any kind of separator:

12345

Now I want this string to converted into a list of individual digits

[1,2,3,4,5]

I've tried both

numlist = map(int,input().split(""))

and

numlist = map(int,input().split(""))

Both of them give me Empty Separator error. Is there any other function to perform this task?

Answer 1

You don't need to use split here:

>>> a = "12345"    
>>> map(int, a)
[1, 2, 3, 4, 5]

Strings are Iterable too

For python 3x:

list(map(int, a))

Answer 2

Use list_comprehension.

>>> s = "12345"
>>> [int(i) for i in s]
[1, 2, 3, 4, 5]

Answer 3

The answers are brilliant. Here is an approach using regex

>>> import re
>>> s = '12345'
>>> re.findall(r'\d',s)
['1', '2', '3', '4', '5']

Ref - Docs on Regex

Why use regex for everything?

Answer 4

You also can use

>>> range(1,6)
[1, 2, 3, 4, 5]