python nested list on second item

Question

i have a nested list that needs to be sorted alphabetic on index 1

example:

some_list = [
    [85, u'Bounty Prizes'],
    [34, u'Agent Mission Time Bonus Reward'],
    [46, u'Brokers Fee'],
    [83, u'Contract Reward Deposited'],
    [17, u'Bounty Prize'],
    [1, u'Player Trading'],
    [15, u'Repair Bill'],
    [10, u'Player Donation']
]

sorted(some_list)

but this sorts on index 0. how can I sort on the second item?

Thanks, I guess i missed that one while googling – Hans de Jong Apr 02 '15 at 18:20 — Hans de Jong, Apr 02 '15 at 18:20
Thanks a lot! I reached 10k coz of your edit – Bhargav Rao Apr 02 '15 at 18:21 — Bhargav Rao, Apr 02 '15 at 18:21

Bhargav Rao · Accepted Answer · 2015-04-02T18:07:08.823

5

Use the key argument to the sorted function

sorted(some_list, key = lambda x:x[1])

Refer: The documentation for sorted

key specifies a function of one argument that is used to extract a comparison key from each list element

Another way

>>> import operator
>>> sorted(some_list, key = operator.itemgetter(1))

edited Apr 02 '15 at 18:07

answered Apr 02 '15 at 18:02

Bhargav Rao

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python nested list on second item

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